P11-4A The elementary, irreversible, organic liquid-phase reaction A+B C is carried out adiabatically in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volumetric flow rate is 2 dm³/s and CA0 = 0.1 kmol/m³. Additional information: H(273 K)=-20 kcal/mol, Hg (273 K) = -15 kcal/mol, H(273 K)=-41 kcal/mol = CP CP = 15 cal/mol-K Cpc = 30 cal/mol K k = 0.01 dm³ mol s at 300 K E = 10,000 cal/mol PFR (a) Plot and then analyze the conversion and temperature as a function of PFR volume up to where X=0.85. Describe the trends. (b) What is the maximum inlet temperature one could have so that the boiling point of the liquid (550 K) would not be exceeded even for complete conversion? (c) Plot the heat that must be removed along the reactor (Q vs. V) to maintain isothermal operation.

1. The reaction A → B is to be carried out isothermally in a continuous-flow reactor. The entering volumetric flow rate (v.) is 8 L/h. For a constant volumetric flow rate v = Do, then FA CAVO Also, CAO FAO/vo. Pure species A enters into the reactor at a rate of 4 mol/h. Calculate both the CSTR and PFR volumes necessary to consume 99% of species A (i.e., CA = 0.01CAo) assuming the reaction rate -гA is a. -TAKA with kA = 0.05 mol/L.h b. rA KACA with kA = 0.0001 s¨¹ C. -TA KA(CA)² with kA = 300 L/mol.h 2. Repeat parts a, b, and c above to calculate the time necessary to consume 99.9% of species A in a 1,000 L constant-volume batch reactor with CA。 = 0.5 mol/L.

5. [ , The isothermal and isobaric gas phase reaction: A → 2B follows an elementary rate law. The rate constant k = 1.5 s' when the reaction temperature is at T = 350 K. Pure A is fed into a continuous-stirred tank reactor (CSTR) at a volumetric flow rate of 5 dm/s. What conversion of A can the reactor achieve if the reactor has a volume of 20 dm?

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