P-value = 0.072, a = 0.05 O reject Ho O do not reject Ho P-value = 0.005, a = 0.001 O reject Ho O do not reject Ho P-value = 0.496, α = 0.05 O reject Ho O do not reject Ho P-value = 0.072, a = 0.10 O reject Ho O do not reject Ho P-value = 0.023, α = 0.01 O reject Ho O do not reject Ho P-value = 0.236, a = 0.10 O reject Ho O do not reject Ho

Q: 6+w=4

A: The give equation is 6 + w = 4To find the value of w.

Q: 3y² - 2y-1 (-)-5y²- 2y +6

A:

Q: 64y2+7=32

A: 64y2+7=32

Q: n is the same as 239 added to the product of 238 and z

A:

Q: -5 • -1/7 • 4/8

A: Refer to the we have to find the product of the -5 • -1/7 • 4/8

Q: 1+2x=77

A:

Q: Find A. A= (4A)-¹ = 3 2 22

A:

Q: -12+(4• 3) (-) I 2-14 - 3)ENTER

A:

Q: 2x Ax) = %3D 2 - 1

A:

Q: ^2 for the scor

A: to find (sum of x)2 x= 1,5,4

Q: -4d = -64

A: Given  -4d=-64

Q: Find fre dz |2e*dx

A:

Q: S V25 – 4x²

A: For the solution follow the next step.

Q: Q5/ Find A-в, if: 1 2 3 - 2 1 B = 2 A = 2 -1 0 1 3 - 1

A:

Q: 7+9=?

A: We need to find the sum of 7 and 9

Q: 2: Find: L-1[: 1 3 - 3]

A:

Q: p dx. -3x (h)

A:

Q: 4a5b• V18a3b6

A: We have to find

Q: 2t2 – 100 = 0 %3D

A: The solution is, t = ±5√2  The detailed solution is as follows below:

Q: 6+197

A: Given,          6+197

Q: Find L s²-8

A:

Q: Find

A: We know that,                         ∫1xdx=lnx+ c We need to find  ∫4xdx

Q: 2+36=38

A: Given 2+ 36 = 38  Yes the given statement is true .

Q: dx 4е2я — 8ет + 5

A: This question can be solved using the concept of special integrals.

Q: z? - 34z + 818 = 0

A:

Q: 6z=36

A: