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(P₁ V P2)→q ¬(P₁ V P2) V q = (P₁ AP2) V q = q V (P₁ AP2) = (qVp₁) ^ (q V-p2) = (P₁ Vq)^(-P2 Vq) = (P₁ →q) ^ (P2 → q)

(P₁ V P2)→q ¬(P₁ V P2) V q = (P₁ AP2) V q = q V (P₁ AP2) = (qVp₁) ^ (q V-p2) = (P₁ Vq)^(-P2 Vq) = (P₁ →q) ^ (P2 → q)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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for discrete math, which named logical equivalence is used to justify each step?

(P₁ V P2)→q ¬(P₁ V P2) V q = (P₁ AP2) V q = q V (P₁ AP2) = (qVp₁) ^ (q V-p2) = (P₁ Vq)^(-P2 Vq) = (P₁ →q) ^ (P2 → q)
Transcribed Image Text:(P₁ V P2)→q ¬(P₁ V P2) V q = (P₁ AP2) V q = q V (P₁ AP2) = (qVp₁) ^ (q V-p2) = (P₁ Vq)^(-P2 Vq) = (P₁ →q) ^ (P2 → q)
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