Π Step 5 webassign.net/web/Student/Assignment-Responses/submit?dep=31610596&tags=autosave#question3798304_6 Now, our goal is to find a power series for Step 6 Factor-1 from the numerator and 2 from the denominator. This will give us 2-x 1 Step 4 Therefore, we get -2=-( 1 Now, we can say that In(2-x) = - =— 00 We have In (2-x) = C - 11 -Σ n=0 n=0 After integrating the power series, we have C- ΙΣ n=0 1/₁²/201 +7+1 20(n + 1) t come back) and then integrate it. 00 = C- 00 B n=1 dx. +7+1 (n+1) (2)" 2" (n+1) In order to find C, we let x = 0 and get f(0) = n() = c - (_______ and so C =
Π Step 5 webassign.net/web/Student/Assignment-Responses/submit?dep=31610596&tags=autosave#question3798304_6 Now, our goal is to find a power series for Step 6 Factor-1 from the numerator and 2 from the denominator. This will give us 2-x 1 Step 4 Therefore, we get -2=-( 1 Now, we can say that In(2-x) = - =— 00 We have In (2-x) = C - 11 -Σ n=0 n=0 After integrating the power series, we have C- ΙΣ n=0 1/₁²/201 +7+1 20(n + 1) t come back) and then integrate it. 00 = C- 00 B n=1 dx. +7+1 (n+1) (2)" 2" (n+1) In order to find C, we let x = 0 and get f(0) = n() = c - (_______ and so C =
Chapter9: Sequences, Probability And Counting Theory
Section9.5: Counting Principles
Problem 42SE: In horse racing, a “trifecta” occurs when a bettor wins by selecting the first three finishers in...
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