Π Step 5 webassign.net/web/Student/Assignment-Responses/submit?dep=31610596&tags=autosave#question3798304_6 Now, our goal is to find a power series for Step 6 Factor-1 from the numerator and 2 from the denominator. This will give us 2-x 1 Step 4 Therefore, we get -2=-( 1 Now, we can say that In(2-x) = - =— 00 We have In (2-x) = C - 11 -Σ n=0 n=0 After integrating the power series, we have C- ΙΣ n=0 1/₁²/201 +7+1 20(n + 1) t come back) and then integrate it. 00 = C- 00 B n=1 dx. +7+1 (n+1) (2)" 2" (n+1) In order to find C, we let x = 0 and get f(0) = n() = c - (_______ and so C =
Π Step 5 webassign.net/web/Student/Assignment-Responses/submit?dep=31610596&tags=autosave#question3798304_6 Now, our goal is to find a power series for Step 6 Factor-1 from the numerator and 2 from the denominator. This will give us 2-x 1 Step 4 Therefore, we get -2=-( 1 Now, we can say that In(2-x) = - =— 00 We have In (2-x) = C - 11 -Σ n=0 n=0 After integrating the power series, we have C- ΙΣ n=0 1/₁²/201 +7+1 20(n + 1) t come back) and then integrate it. 00 = C- 00 B n=1 dx. +7+1 (n+1) (2)" 2" (n+1) In order to find C, we let x = 0 and get f(0) = n() = c - (_______ and so C =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:←
Step 4
Now, our goal is to find a power series for -
Step 5
Find a power
webassign.net/web/Student/Assignment-Responses/submit?dep=31610596&tags=autosave#question3798304_6
Step 6
Factor-1 from the numerator and 2 from the denominator. This will give us
Therefore, we get -
Now, we can say that In(2-x) = -=
- x
After integrating the power series, we have C - ¹
Σ
Need Help?
n=0
We have In(2-x) = C - +1
27(n + 1)
24
n=0
Submit Skip (you cannot come back)
Read It
2-x
In order to find C, we let x = 0 and get f(0) =
₁ - - - 201
and then integrate it.
= C-
n=0
B)
n=1
dx.
x+1
(n+1)(2)"
)=c-(
G36.00/40.00
2" (n + 1)
and so C =
Ebooks -Cen x
WPsWk13-S
X
3. [2/4
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