p = mv J = Ft Ft = m Av What impulse is needed to stop a 1700 kg car in 15 seconds if it was originally moving at 25 m/s?

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Chapter1: Units, Trigonometry. And Vectors
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### Understanding Impulse and Momentum

Impulse and momentum are fundamental concepts in physics that describe the motion of objects. Here's a breakdown of the key principles and equations involved:

#### Key Equations:
1. **Momentum (p)**
   \[
   p = mv
   \]
   * \( p \) = momentum
   * \( m \) = mass (in kilograms)
   * \( v \) = velocity (in meters per second)

2. **Impulse (J)**
   \[
   J = Ft
   \]
   * \( J \) = impulse
   * \( F \) = force applied (in Newtons)
   * \( t \) = time over which the force is applied (in seconds)

3. **Impulse-Momentum Theorem**
   \[
   Ft = m \Delta v
   \]
   * \( F \) = force
   * \( t \) = time
   * \( m \) = mass
   * \( \Delta v \) = change in velocity

#### Problem Statement
What impulse is needed to stop a 1700 kg car in 15 seconds if it was originally moving at 25 m/s?

To solve this problem, we need to find the impulse (\( J \)) required to bring the car to a stop. We are given:
- Mass of the car (\( m \)) = 1700 kg
- Initial velocity (\( v \)) = 25 m/s
- Final velocity (\( v_f \)) = 0 m/s (since the car stops)
- Time (\( t \)) = 15 seconds

Using the Impulse-Momentum Theorem (\( Ft = m \Delta v \)), we can calculate the impulse.

First, determine the change in velocity (\( \Delta v \)):
\[
\Delta v = v_f - v = 0 - 25 = -25 \, \text{m/s}
\]

Then, calculate the impulse:
\[
J = m \Delta v
\]
\[
J = 1700 \times (-25)
\]
\[
J = -42500 \, \text{Ns}
\]

The negative sign indicates that the impulse is in the direction opposite to the car's initial motion in order to bring it to a stop. Thus, the magnitude of the impulse needed is **42500 Ns**.

This example illustrates how to apply the
Transcribed Image Text:### Understanding Impulse and Momentum Impulse and momentum are fundamental concepts in physics that describe the motion of objects. Here's a breakdown of the key principles and equations involved: #### Key Equations: 1. **Momentum (p)** \[ p = mv \] * \( p \) = momentum * \( m \) = mass (in kilograms) * \( v \) = velocity (in meters per second) 2. **Impulse (J)** \[ J = Ft \] * \( J \) = impulse * \( F \) = force applied (in Newtons) * \( t \) = time over which the force is applied (in seconds) 3. **Impulse-Momentum Theorem** \[ Ft = m \Delta v \] * \( F \) = force * \( t \) = time * \( m \) = mass * \( \Delta v \) = change in velocity #### Problem Statement What impulse is needed to stop a 1700 kg car in 15 seconds if it was originally moving at 25 m/s? To solve this problem, we need to find the impulse (\( J \)) required to bring the car to a stop. We are given: - Mass of the car (\( m \)) = 1700 kg - Initial velocity (\( v \)) = 25 m/s - Final velocity (\( v_f \)) = 0 m/s (since the car stops) - Time (\( t \)) = 15 seconds Using the Impulse-Momentum Theorem (\( Ft = m \Delta v \)), we can calculate the impulse. First, determine the change in velocity (\( \Delta v \)): \[ \Delta v = v_f - v = 0 - 25 = -25 \, \text{m/s} \] Then, calculate the impulse: \[ J = m \Delta v \] \[ J = 1700 \times (-25) \] \[ J = -42500 \, \text{Ns} \] The negative sign indicates that the impulse is in the direction opposite to the car's initial motion in order to bring it to a stop. Thus, the magnitude of the impulse needed is **42500 Ns**. This example illustrates how to apply the
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