College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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**Question 8: Temperature Conversion for Oxygen Condensation**

**Context:**
Oxygen condenses into a liquid at approximately 90 Kelvin (K). To understand this in terms of the Fahrenheit scale, we need to determine what temperature 90 K corresponds to in degrees Fahrenheit (°F).

**Question:**
At what temperature, in degrees Fahrenheit, does 90 K correspond to?

**Answer Choices:**
A) -193°F  
B) -265°F  
C) -297°F  
D) -217°F

To solve this problem, one must convert the temperature from Kelvin to Fahrenheit using the formula:

\[ °F = \frac{9}{5}(K - 273.15) + 32 \]

By applying this formula for K = 90:

1. Subtract 273.15 from 90:  
\[ 90 - 273.15 = -183.15 \]

2. Multiply the result by \(\frac{9}{5}\):  
\[ \frac{9}{5} \times (-183.15) = -329.67 \]

3. Add 32 to the result:  
\[ -329.67 + 32 = -297.67 \]

Thusly, when rounded, the temperature 90 K corresponds to approximately -298°F.

Therefore, the correct answer is:  
C) -297°F
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Transcribed Image Text:**Question 8: Temperature Conversion for Oxygen Condensation** **Context:** Oxygen condenses into a liquid at approximately 90 Kelvin (K). To understand this in terms of the Fahrenheit scale, we need to determine what temperature 90 K corresponds to in degrees Fahrenheit (°F). **Question:** At what temperature, in degrees Fahrenheit, does 90 K correspond to? **Answer Choices:** A) -193°F B) -265°F C) -297°F D) -217°F To solve this problem, one must convert the temperature from Kelvin to Fahrenheit using the formula: \[ °F = \frac{9}{5}(K - 273.15) + 32 \] By applying this formula for K = 90: 1. Subtract 273.15 from 90: \[ 90 - 273.15 = -183.15 \] 2. Multiply the result by \(\frac{9}{5}\): \[ \frac{9}{5} \times (-183.15) = -329.67 \] 3. Add 32 to the result: \[ -329.67 + 32 = -297.67 \] Thusly, when rounded, the temperature 90 K corresponds to approximately -298°F. Therefore, the correct answer is: C) -297°F
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