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- Draw the alkene that would react with the reagent given to account for the product formed. CH3 HCI CH3 CHCCH, ? + Či CH3 You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one.Draw the alkene that would react with the reagent given to account for the product formed. ? + + H₂O **** H₂S04 • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. CH3 CH3 CHCCH3 | | OH CH3 +1When carbonyl compounds are reduced with a reagent such as LiAlH4 or NaBH4 and a new stereogenic center is formed, what will the composition of the product mixture be? Forms more of one enantiomer than another because of steric reasons around the carbonyl Forms more of one enantiomer than another depending on the temperature of the reaction Forms different products depending on the solvent used Forms a racemic mixture of the two possible enantiomers
- What is the substitution product of the reaction of CH3CH(CH3)CH2(CH2)2Br with OH-? A) CH₂OHCH(CH3)(CH2)2CH₂Br B) CH3CH(CH3)CH₂CHOHCH3 C) CH3CH(CH3)CH₂(CH2)2OH D) CH3CH(CH3)CH₂CHOHCH2₂BrDraw the alkene that would react with the reagent given to account for the product formed. ? + HCI CH3 CH3CCH3 CI • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. #[ ] در ChemDoodleSelect the missing reagent for the reaction seen below: HCI Cl2 / FeCl3 Cl2 / AICI3 Cl2 CI
- Name the following structures. 1. CH3CH2CH2CH2COOCH2CH3 2. CH3CH2CH2CH2COOCH2CH2CH3 3. CH≡CCHCOOCH2CH3 4. CH2=CHCH2COOCH2CH2CH3 5. CH3CH2CH2COOCH3 6. CH3CH2CH2CH2CH2CH2CH2COOCH2CH2CH2CH2CH3 7. CH3CH=CHCH2COOCH3 8. CH3CH2CH2COOCH2CH3 9. CH3CH2CH2CH2CH2CH2COOCH2CH2CH2CH2CH2CH3 10. CH2CH=CHCH2COOCH2CH2CH2CH3Which of the following reactions require ethereal solution? a. CH3CH=CH2 to CH3CH2CH3 b. CH3CH=CH2 to CH3CH2CH2Cl c. CH3CH=CH2 to CH3CH2CH2-OH d. CH3CH=CH2 to CH3CHBrCH2BrDetermine the double bond stereochemistry (E or Z) for the following molecules. F. H3C C A CH3 F. H B D Br
- For the trans isomer of cinnamic acid: o Draw the structure of the trans isomer of cinnamic acid and the structure of the intermediate bromonium ion. Note that the bromonium ion can exist as two enantiomeric forms. You should draw both of these isomeric forms. o Draw the structures of the two dibrominated products which can form when a bromide ion adds to the bromonium ion intermediate. These must be drawn to show the correct stereochemistry. Assign the chiral carbons as R or S.Give the systematic (IUPAC) name for each molecule. CH3CCH3 systematic (IUPAC) name: CH3CH2CH2CCH3 systematic (IUPAC) name: terms of Use contact us help ebout us careers privacy policy 7:29 PMCurved arrows are used to illustrate the flow of electrons. Follow the arrows and draw the intermediate and product in this reaction. Include all lone pairs. Ignore stereochemistry. Ignore inorganic byproducts. H₂C :0: Draw Tetrahedral Intermediate loss of CH3CH₂CO2™ Draw Product