Out of 400 people sampled, 368 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to four places < p <

Q: In a recent poll, 300 people were asked if they liked dogs, and 54% said they did. Find the Margin…

A: Obtain the margin of error for the poll at the 95% confidence level. The margin of error for the…

Q: A survey of 100 americans found that 68% said they find it hard to buy holiday gifts that convey…

A: It is given that, p hat is 0.68 and the sample size (n) is 100.  The level of confidence is 0.90.

Q: Out of 100 people sampled, 77 had kids. Based on this, construct a 95% confidence interval for the…

A: We have to find 95% confidence interval for the true population proportion of people with kids.

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: In a survey of 2274 adults, 749 say they believe in UFOs. Construct a 99% confidence interval for…

A:

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: If n = 230 and X = 184, construct a 99% confidence interval for the population proportion, p.Give…

A: Given data n = 230 x = 184 sample proportion

Q: Out of 500 people sampled, 190 had kids. Based on this, construct a 90% confidence interval for the…

A: Given : Sample Size, n = 500 Number of successes, x = 190 confidence level,c=0.9

Q: Out of 100 people sampled, 35 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: A poll of 1785 U.S. adults found that 900 U.S. adults, or 50.42% regularly used Facebook as a news…

A: Given that: Sample proportion, p^=0.5042 sample size (n) =900

Q: A survey of 100 men found that 68% said they find it hard to buy holiday gifts that convey their…

A: Solution

Q: Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying…

A: Solution: Given that, Estimate the proportion of students on her campus who eat cauliflower n=20 #…

Q: Express the confidence interval (77.4 % , 89.2 % ) in the form of p ± ME.

A: GivenConfidence Interval(77.4% , 89.2%)

Q: Express the form of most of the confidence intervals that you will encounter in your study of…

A: Confidence Interval:Confidence interval is the interval estimate of the population parameter. It is…

Q: In a recent poll, 450 people were asked if they liked dogs, and 54% said they did. Find the Margin…

A: Solution

Q: A survey was conducted that asked 1004 people how many books they had read in the past year. results…

A:

Q: find tc for a 95% confidence level when the sample size is 6.

A: level of significance, alpha = 0.05from standard normal table, two tailed t alpha/2 with n-1 = 6 d.f…

Q: Out of 300 people sampled, 282 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: Find the confidence level and α for an 80​% confidence interval.

A: Given confidence level =80%

Q: If n= 100 and x= 80, construct a 99% confidence interval.  Give your answers to three decimals

A:

Q: In a recent poll, 490 people were asked if they liked dogs, and 90% said they did. Find the Margin…

A: Given, n=490p∧=90%=0.90 Confidence Interval=(1-α)·100%=99%                         i.e.,  α=0.01

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.