Out of 300 people sampled, 135 received flu vaccinations this year. Based on this, construct a 95% confidence interval for the true population proportion of people who received flu vaccinations this year. Give your answers as decimals, to three places |

Q: Wildlife biologists inspect 200 deer taken by hunters and find 45 of them carrying Lyme disease…

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Q: In a recent poll, 300 people were asked if they liked dogs, and 54% said they did. Find the Margin…

A: Obtain the margin of error for the poll at the 95% confidence level. The margin of error for the…

Q: In a recent poll, 420 people were asked if they liked dogs, and 9% said they did. Find the Margin of…

A: Given: Sample size=n=420,Number of people who liked dogs:x=420×9100=37.8≈38,Significance…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: Construct a confidence interval of the population proportion at the given level of confidence.…

A: Givenx=540n=1200confidence interval = 96%

Q: 95% confidence interval for the true percent of workers in this city who have full health insurance…

A: The question is about confidence interval.Given :Randomly selected no. of workers ( n ) = 1700No. of…

Q: Out of 400 people sampled, 240 had kids. Based on this, construct a 95% confidence interval for the…

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Q: In a recent poll, 270 people were asked if they liked dogs, and 15% said they did. Find the Margin…

A: given data sample size (n) = 270p^ = 0.1595% ci p, E = ?

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: A poll of 1468 U.S. adults found that 44% regularly used Facebook as a news source. Find the…

A: Given information Sample size (n) = 1468

Q: Out of 200 people sampled, 72 had kids. Based on this, construct a 90% confidence interval for the…

A: Givensample size(n)=200x=72sample proportion(p^)=xn=72200=0.36Confidence level=90%

Q: Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use…

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Q: construct a 95% confidence interval for the true population proportion of people with kids.

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Q: Out of 300 people sampled, 228 had kids. Based on this, construct a 90% confidence interval for the…

A: Introduction Sample size, n=300 No. of people who had kids, x=228 CL=0.90

Q: A poll of 2929 U.S. adults found that 85% regularly used Facebook as a news source. Find the…

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Q: In each of Exercises, answer true or false to each statement concerning a confidence interval for a…

A: The margin of error for each confidence interval (E) is obtained as follows:

Q: In a recent poll, 310 people were asked if they liked dogs, and 40% said they did. Find the Margin…

A: Given data: n = 310p⏞ = 40100=0.40C.I = 99%      =0.99Then, calculate αα = 1-0.99   =0.01Now,…

Q: A poll of 1785 U.S. adults found that 900 U.S. adults, or 50.42% regularly used Facebook as a news…

A: Given that: Sample proportion, p^=0.5042 sample size (n) =900

Q: Find ??/2 for the 93% confidence interval. Select one: A. 1.83 B. 1.81 C. 1.80 D. 1.82

A: Solution: Given information: Confidence level = 93% = 0.93 α=1-confidence level α=1-0.93= 0.07…

Q: In a survey of 323 adults over 50, 60% said they were taking vitamin supplements. Find the margin of…

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Q: x=111, n=194, Confidence level = 99%

A: The sample proportion of p is, p^=xn=111194=0.5722 Computation of critical value:…

Q: A poll of 2657 U.S. adults found that 86% regularly used Facebook as a news source. Find the margin…

A: Given that, n = 2657 Point estimate = sample proportion =  = 0.86 1 -  = 1 - 0.86 = 0.14

Q: A poll of 2977 U.S. adults found that 28% regularly used Facebook as a news source. Find the margin…

A: Solution: Given information: n = 2977 Sample size  p^= 0.28  Sample proportion.

Q: Construct the confidence interval for the population mean . C=0.98, x=15.3, = 10.0, and n=75

A: The Confidence Interval formula is X  ±  Z s √(n) Where: X is the mean Z is the Z-value…

Q: Use the given data to construct a confidence interval of the requested level. X = 178, N=531,…

A: Given : Sample Size, n = N = 531 Number of successes, x = 178

Q: In a recent poll, 260 people were asked if they liked dogs, and 80% said they did. Find the Margin…

A: Given:

Q: In a recent poll, 300 people were asked if they liked dogs, and 71% said they did. Find the Margin…

A:

Q: in a recent poll, 130 people were asked if they liked dogs, and 46% said they did. Find the Margin…

A: Introduction: The 100 (1 – α) % confidence interval for the population proportion, p is: Here, n is…

Q: Construct a confidence interval of the population proportion at the given level of confidence. X =…

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Q: Determine tc for n = 15 and a confidence level of 99%.

A: From the given information, Sample size (n) =15, Confidence level (1-α)= 0.99 Thus, the t-critical…

Q: If n = 220 and X = 176, construct a 95% confidence interval for the population proportion, p. Give…

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Q: Out of 500 people sampled, 95 had kids. Based on this, construct a 90% confidence interval for the…

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Q: A poll of 1021 U.S. adults found that 46% regularly used Facebook as a news source. Find the…

A: Given, n = 1021 p^=0.46 q^ = 1 - p^ = 1 - 0.46 = 0.54 α=0.1

Q: In a recent poll, 490 people were asked if they liked dogs, and 51% said they did. Find the Margin…

A: Given data,n=490p=51%=0.51z-value at 99% confidence is Zc=2.576E=?

Q: If n=550 and X = 440, construct a 90% confidence interval. Give your answers to three decimals <p<

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Q: In a recent poll, 190 people were asked if they liked dogs, and 81% said they did. Find the Margin…

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Q: Out of 400 people sampled, 76 had kids. Based on this, construct a 90% confidence interval for the…

A: Find z-critical value:…

Q: A poll of 2368 U.S. adults found that 40% regularly used Facebook as a news source. Find the margin…

A: Solution: From the given information, n=2368, p-hat = 40%. The confidence level is 0.90.

Q: In a recent poll, 230 people were asked if they liked dogs, and 72% said they did. Find the Margin…

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.