our sample size is 30. a)According to the histograms, is the normality of the populations condition met? Group of answer choices Yes, at least one of the sample distributions appears to be normal. Yes, there are no outliers in the histograms of the three sample distributions. No, normality is not a condition for ANOVA. No, there is clear skewness and outliers in all the sample distributions. B)Calculate the standard deviations of the plant weights in each group. Is the equal population standard deviation met? Group of answer choices No, .58 does not equal .79 or .44. Yes, .79/.58 equals 1.36, which is less than 2. Yes, .44/.79 equals .55, which is less than 2. Yes, .79/.44 equals 1.80, which is less than 2.
our sample size is 30. a)According to the histograms, is the normality of the populations condition met? Group of answer choices Yes, at least one of the sample distributions appears to be normal. Yes, there are no outliers in the histograms of the three sample distributions. No, normality is not a condition for ANOVA. No, there is clear skewness and outliers in all the sample distributions. B)Calculate the standard deviations of the plant weights in each group. Is the equal population standard deviation met? Group of answer choices No, .58 does not equal .79 or .44. Yes, .79/.58 equals 1.36, which is less than 2. Yes, .44/.79 equals .55, which is less than 2. Yes, .79/.44 equals 1.80, which is less than 2.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
our
a)According to the histograms, is the normality of the populations condition met?
Group of answer choices
Yes, at least one of the sample distributions appears to be normal.
Yes, there are no outliers in the histograms of the three sample distributions.
No, normality is not a condition for ANOVA.
No, there is clear skewness and outliers in all the sample distributions.
B)Calculate the standard deviations of the plant weights in each group. Is the equal population standard deviation met?
Group of answer choices
No, .58 does not equal .79 or .44.
Yes, .79/.58 equals 1.36, which is less than 2.
Yes, .44/.79 equals .55, which is less than 2.
Yes, .79/.44 equals 1.80, which is less than 2.
Transcribed Image Text:The image displays a web interface from the URL shinyserver.byu.edu, used for drawing histogram plots. It shows three separate histograms representing different sample groups labeled as "ctrl," "trt1," and "trt2."
### Graph Description:
1. **Histograms**:
- **Ctrl (Control Group)**:
- The x-axis represents weight, ranging from 3.5 to 6.0.
- The y-axis represents the count of occurrences.
- The distribution shows a peak at approximately 5.0 with a count of 3. Other values are dispersed between 4.0 and 5.5.
- **Trt1 (Treatment 1 Group)**:
- The x-axis also represents weight values from 3.5 to 6.0.
- The y-axis represents the count.
- The distribution appears relatively flat with counts between 1 to 2 across weights ranging from 3.5 to 6.0. There is no distinct peak.
- **Trt2 (Treatment 2 Group)**:
- The x-axis contains weight values from 3.5 to 6.0.
- The y-axis shows the count.
- The histogram indicates peaks at weight intervals around 5.0 to 5.5 with a count of 2, with some values extending up to 6.0.
### Interface Features:
- **Dropdown Menu**: An option to select "Histograms" from the dropdown menu to draw the plot.
- **Question Prompt**: Below the histogram, there is a question prompting the user to choose which numerical summary they would like to calculate for each group.
- **Buttons**: An option to "Proceed to Statistical Inference."
This interface could be used for exploratory data analysis in a statistics course, allowing students to visualize and interpret data distributions across different experiment groups.
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