|Three forces F, = 20 N, F, = 10 N and F, = 5.0 N act on the structure shown in figure below. A fourth force F, to be applied at a point P on the structure to keep it in equilibrium. The fourth force has two components Fv and Fh. Given that a = 2.0 m, b = 3.0 m and c = 1.0 m, Calculate Fh, Fv and d k d

3 14 F The horizontal force F pulls a heavy suspended mass to the side. al force p DO In static equilibrium, the angle is constant. If m = 74.70 kg, and the angle = 33.60 degrees, then what is F? (in N) OA: 303.99 B: 355.67 OC: 416.13 OD: 486.88 OE: 569.64 OF: 666.48 OG: 779.79 OH: 912.35

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Need in 20mins urgent plsss

16. ao The drawing shows a rectangular piece of wood. The forces applied to corners B and D have the same magnitude of 12 N and are directed parallel to the long and short sides of the rectangle. The long side of the rectangle is twice as long as the short side. An axis of ro- tation is shown perpendicular to the plane of the rectangle at its center. A third force (not shown in the drawing) is applied to cor- ner A, directed along the short side of the rectangle (either toward B or away from B), such that the piece of wood is at equilib- rium. Find the magnitude and direction of the force applied to corner A. A D Axis Problem 16

Which of the following sets of concurrent forces are in equilibrium? O a. F1 = 12, F, = 12, F; = 15 %3D O b. F, = 12, F, = 12, F, = 15 F = 9, F2 = 12, F; = 15 Od. F; = 15, F2 = 12, F3 = 15 O e. Fy = 9, F2 = 12, F3 = 9

i need the answer quickly

{-360k } lb, 2–105. If the resultant of the four forces is FR determine the tension developed in each cable. Due to symmetry, the tension in the four cables is the same. Z. E FA Fc 6 ft FD D A C 2 ft 2 ft 3 ft 3 ft Probs. 2–104/105

The 6-m pole ABC is acted upon by a 460-N force, P, as shown in the figure. The pole is held by a ball-and-socket joint at A and by two cables BD and BE. For a = 3 m, determine the tension in each cable and the reaction at A. (Round the final answers to one decimal place.) 3. 1.5 m P E The tension in cable BD is The tension in cable BE is The reaction at A is - ( y C B 3 m N. N. N)i + 3 m 3 m 1.5 m 3 m X N)j + N)k.

What are the forces Ax, Ay and B 20 points if the body is in Equilibrium ? 30° 0.2 m A, 400 N A, 0.2 m 0.5 m B