| ssm In exercising, a weight lifter loses 0.150 kg of water *7. through evaporation, the heat required to evaporate the water com- ing from the weight lifter's body. The work done in lifting weights is 1.40 x 10° J. (a) Assuming that the latent heat of vaporization of perspiration is 2.42 X 10° J/kg, find the change in the internal energy of the weight lifter. (b) Determine the minimum number of nutritional Calories of food (1 nutritional Calorie = 4186 J) that must be consumed to replace the loss of internal energy.

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Chapter20: The First Law Of Thermodynamics
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| ssm In exercising, a weight lifter loses 0.150 kg of water
*7.
through evaporation, the heat required to evaporate the water com-
ing from the weight lifter's body. The work done in lifting weights is 1.40 x
10° J. (a) Assuming that the latent heat of vaporization of perspiration is
2.42 X 10° J/kg, find the change in the internal energy of the weight lifter.
(b) Determine the minimum number of nutritional Calories of food
(1 nutritional Calorie = 4186 J) that must be consumed to replace the
loss of internal energy.
Transcribed Image Text:| ssm In exercising, a weight lifter loses 0.150 kg of water *7. through evaporation, the heat required to evaporate the water com- ing from the weight lifter's body. The work done in lifting weights is 1.40 x 10° J. (a) Assuming that the latent heat of vaporization of perspiration is 2.42 X 10° J/kg, find the change in the internal energy of the weight lifter. (b) Determine the minimum number of nutritional Calories of food (1 nutritional Calorie = 4186 J) that must be consumed to replace the loss of internal energy.
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