One half-cell in a voltaic cell is constructed from a copper wire electrode in a 3.9 × 10¬³ M solution of Cu(NO3)2 . The other half-cell consists of a zinc electrode in a 0.45 M solution of Zn(NO3)2. Calculate the cell potential. You may need to use the following data: Zn²+ (aq) + 2 e¯ → Zn(s) Cu²+ (aq) + 2 e¯ → Cu(s) E° =+0.337 V E° = -0.763 V

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M solution of Cu(NO3)2. The other half-cell consists of a zinc electrode in
One half-cell in a voltaic cell is constructed from a copper wire electrode in a 3.9 x 10
a 0.45 M solution of Zn(NO3)2 . Calculate the cell potential.
You may need to use the following data:
Zn²+ (aq) + 2 e¯ → Zn(s) E° = -0.763 V
Cu²+ (aq) + 2 e¯ →
Cu(s) E° = +0.337 V
Potential =
V
Transcribed Image Text:-3 M solution of Cu(NO3)2. The other half-cell consists of a zinc electrode in One half-cell in a voltaic cell is constructed from a copper wire electrode in a 3.9 x 10 a 0.45 M solution of Zn(NO3)2 . Calculate the cell potential. You may need to use the following data: Zn²+ (aq) + 2 e¯ → Zn(s) E° = -0.763 V Cu²+ (aq) + 2 e¯ → Cu(s) E° = +0.337 V Potential = V
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