One form of nuclear
Suppose an electron is ejected from a 3H atom, which has a radius of 1.000×10-14 m. The resulting 3He atom has the same radius as the 3H atom. What is the escape velocity of the electron ejected from the process?
Note: Your answer may be larger than the speed of light which is okay in this scenario. To solve this problem correctly we would need to use
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- A 60-kg person accidentally ingests a small source of alpha particles (RBE=15). The activity of the source is 0.04 Ci, the half-life of the source is 110 years, and each alpha particle emitted has an energy of 0.586 MeV. It takes 12 hours for the alpha source to pass through the person’s digestive system and exit the body.i. How many alpha particles are absorbed by the person (assume that 100 percent of the alpha particles emitted by the source are absorbed by the person)? ii. How much energy, in Joules, is deposited in the person by the source?iii. What is the absorbed dose in rad? iv. What is the absorbed dose in rem?arrow_forwardin the stable isotope of Potassium 39K there are 19 electrons, 19 protons and 20 neutrons. The mass of the neutral atom is 38.96371 u. Calculate: Total mass / u Mass defect / u Binding energy / J Binding energy / MeV Mass of the proton = 1.007276 u Mass of the neutron = 1.008665 uarrow_forwardScientists can determine the age of ancient objects by the method of radiocarbon dating. The bombardment of the upper atmosphere by cosmic rays converts nitrogen to a radioactive isotope of carbon, 14C, with a half-life of about 5730 years. Vegetation absorbs carbon dioxide through the atmosphere and animal life assimilates ¹4C through food chains. When a plant or animal dies, it stops replacing its carbon and the amount of 14C begins to decrease through radioactive decay. Therefore the level of radioactivity must also decay exponentially. A parchment fragment was discovered that had about 75% as much 14C radioactivity as does plant material on earth today. Estimate the age of the parchment. (Round your answer to the nearest whole number.) yr Need Help? Watch It Additional Materials THERarrow_forward
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- b) Complete the following decay reaction by identifying both the temporary nucleus (??) and the end product (?) that it decays into. In this case, sodium-23 is bombarded with protons, forming a short-lived nucleus which quickly undergoes alpha decay. 2Na+H → (??) → (⁄?) + ª Enter the chemical symbol for the temporary nucleus: Enter the mass number for the end product, A = Enter the atomic number for the end product, Z = Enter the chemical symbol for the end product: AV A/ AV 10arrow_forwardIdentify the isotope notation for the isotope of cadmium that has 54 neutronsarrow_forwardConsider an object of mass 26.1 kg. Assume that it s made up of equal numbers of protons, neutrons, and electrons. How many protons does this object contain? 3.91E+27 7.81E+27 1.56E+28 O 3.12E+28arrow_forward
- Q3: The table shows two isotopes of potassium and two isotopes of calcium. Type of emission Mass of neutral atom / u Number of electrons Number of protons Number of neutrons Total mass/u Mass defect/ u Binding energy / J Mass of the electron = 0.000549 u Mass of the proton = 1.007276 u Mass of the neutron = 1.008665 u TI ***** LEG 39K Stable 38.96371 SE nda 42K ß decay a) Use data about potassium-42 to explain the concept of mass defect. 3000 41.9624 19 19 23 42.34797 0.38557 5.76 x 10-11 De RAP 39 Ca ßt decay 38.9707 440 **** ****** D 42 Ca stable 41.95863arrow_forwardA neutron in a star makes an elastic head-on collision with a carb on nucleus initially at rest. The mass of the carbon nucleus is 12 times the mass of the neutron mn = 1.7 ×10^−27kg. The initial kinetic energy of the neutron is 1.6 × 10^−13J. a) Show that the final speed of the carbon nucleus, Vc, is given by (see image) where vn is the initial speed of the neutron.arrow_forwardUranium (protons = 92, neutrons = 146, atomic mass = 238.050788 u) decays via alpha decay to Thorium (protons = 90, neutrons = 144, atomic mass = 234.043601 u). What is the kinetic energy of the emitted alpha particle? (Hint: Any energy that is not locked up in rest energy of the product nuclei will go to kinetic energy in the alpha particle.) (Hint: the answer is 4.27 MeV)arrow_forward
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