A 57.5-kg grindstone is a solid disk 0.6 m in diameter. You press an ax downon the rim with a normal force of 164.9 N.mThe coefficient of kinetic friction between the blade and the stone is 0.7, andthere is a constant friction torque of 9.5 N m between the axle of the stoneand its bearings. Another force is applied tangentially at the end of a crankhandle 0.5 m long to bring the stone from rest to 164.1 rev/min in 8.1 s.After the grindstone attains an angular speed of 120 rev/min, what tangentialforce at the end of the handle is needed to maintain a constant angular speedof 120 rev>min?*1 = 1/2 MR2

Given:mass of stone, m = 57.5 kgradius, R = 0.62=0.3 mNormal force, N = 164.9 NTorque due to…

Answered: on the rim with a normal force of 164.9…

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on the rim with a normal force of 164.9 N.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).

Question

A 57.5-kg grindstone is a solid disk 0.6 m in diameter. You press an ax down
on the rim with a normal force of 164.9 N.
m
The coefficient of kinetic friction between the blade and the stone is 0.7, and
there is a constant friction torque of 9.5 N m between the axle of the stone
and its bearings. Another force is applied tangentially at the end of a crank
handle 0.5 m long to bring the stone from rest to 164.1 rev/min in 8.1 s.
After the grindstone attains an angular speed of 120 rev/min, what tangential
force at the end of the handle is needed to maintain a constant angular speed
of 120 rev>min?
*1 = 1/2 MR2

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