14 **Physics Problem: Truck Acceleration***Scenario:*A tow truck, by itself, can accelerate at a rate of \(3.0 \, \text{m/s}^2\). Consider the case where this truck is towing a bus that has twice the truck's own mass. What will be the new acceleration of the tow truck?*Options:*- \(2.0 \, \text{m/s}^2\)- \(1.5 \, \text{m/s}^2\)- \(1.0 \, \text{m/s}^2\)- \(2.5 \, \text{m/s}^2\)- none of these*Explanation:*To solve this problem, use Newton’s Second Law. The force exerted by the truck remains constant. Originally, the force \( F \) can be expressed as:\[ F = m \times a = m \times 3.0 \, \text{m/s}^2 \]When towing the bus, the total mass becomes \( 3m \), where \( m \) is the mass of the truck. With the same force applied:\[ F = (3m) \times a' \]Since the force \( F \) remains unchanged, equate the two expressions and solve for \( a' \) (new acceleration):\[ m \times 3.0 = 3m \times a' \]\[ a' = \frac{3.0}{3} = 1.0 \, \text{m/s}^2 \]Thus, the correct choice is \(1.0 \, \text{m/s}^2\).

Given information: The acceleration of the tow truck, a=3.0 m/s2 Let m be the mass of the tow truck The force acting on the truck is given by F=mawhere,m=mass of the trucka=acceleration of the truck Substitute known values F=3m Now, a bus having a mass twice the mass of the truck is attached to the tow truck. The total mass will be equal to m+2m The force acting on the tow truck is given by F=(m+2m)a'F=3ma' From the above two, 3ma'=3ma'=1.0 m/s2 This the acceleration of the tow truck after attached the bus.Answer: The correct option is 1.0 m/s2

Answered: On its own, a tow truck has an…

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On its own, a tow truck has an acceleration of 3.0 m/s². What would be the acceleration when the truck is towing a bus twice its own mass? 2.0 m/s^2 O 1.5 m/s^2 O 1.0 m/s^2 2.5 m/s^2 O none of these