ON 11 Solve the initial value problem. dr Differential Equation: dt Initial Condition: r(0) = -4i + 6k -312- O 00 r(t) = - - + r(t) = -3ti + 3tj + 5tk 51² 2 r(t) 1) = -32²2-4₁+212₁-512²+6k r(t) = (-312-8)i + 312j + (51²+12)k -312-81+2121 52² 12x +
ON 11 Solve the initial value problem. dr Differential Equation: dt Initial Condition: r(0) = -4i + 6k -312- O 00 r(t) = - - + r(t) = -3ti + 3tj + 5tk 51² 2 r(t) 1) = -32²2-4₁+212₁-512²+6k r(t) = (-312-8)i + 312j + (51²+12)k -312-81+2121 52² 12x +
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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QUESTION 11
Solve the initial value problem.
Differential Equation:
Initial Condition: r(0) = -4i + 6k
O
O
r(t) =
r(t) =
-31²-4
2
r(t) =
-312²-
1+
i+
QUESTION 12
Evaluate the integral.
OO
07√2 i +5√√2 j
0 5√2 i
dr
dt
Or(t) = (-3t2-8)i + 3t²j + (51²+12)k
-31²-
7/4
S (7 cos ti + 5 sin tj) dt
-7X/4
7√2i
= -3ti + 3tj + 5tk
2
+
10
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