OK, once again we have a pendulum, this time of length 1.86 m, which you release from rest at an angle of 52.5 degrees to the vertical. What will be the speed of the pendulum at the instant it reaches an angle of 10.5 degrees above the vertical?     3.78 m/s     0.78 m/s     5.67 m/s     3.70 m/s

Q: An ideal spring hangs from the ceiling. A 2.25 kg mass is hung from the spring, stretching the…

A: The value of the spring constant is,

Q: 0.01 m Note: Figere net own to scale.

A: Mass = 0.04 kg Length L = 1.2 m

Q: The figure shows that if we hang a block on the end of a spring with spring constant k, the spring…

A: Given data: Distance h=3.9 cm

Q: A 25kg block on the end of a spring is lifted upward to a point 2 m away from it’s equilibrum…

A: Given mass of the block m = 25kgInitial displacement of the block is 2 meters .Initial velocity of…

Q: A heavy steel ball is hung from a cord to make a pendulum. The ball is pulled to the side so that…

A: Given data The horizontal inclination of the ball is θh = 5°. The vertical inclination of the ball…

Q: This, the length of the pendulum is 2.08 m. Now you start with the pendulum at 13.8 degrees with…

A:

Q: m x=0 x = x₂ i (a) Find the speed the block has as it passes through equilibrium if the horizontal…

A: Mass(m) = 2 kg  Expansion (xi)= 4.60 cm Spring constant (k) = 550 N/m

Q: This, the length of the pendulum is 2.23 m. Now you start with the pendulum at 21.1 degrees with…

A: Length of pendulum =2.23 m initial angle=21.1o final angle=35.2o

Q: A block of mass m 5 Kg is attached to a spring of spring constant k. The block oscillates in simple…

A:

Q: A 5 kg object is attached to a spring and is oscillating on a horizontal surface. When the object…

A:

Q: A block of mass m= 10.0 kg is attached to the end of an ideal spring. Due to the weight of the…

A: Given data:  Mass (m) = 10.0 kg Stretch in spring (h) = 6.00 cm Acceleration due to gravity (g) =…

Q: A block of mnass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in…

A: Given data: Total mechanical energy of the block = 22.5 J m=5 kg Need to determine the maximum…

Q: The motion of a particle connected to a spring is described by x = 10 sin (πt). At what time (in s)…

A:

Q: 10.2 m 16. A simple pendulum consists of a mass M attached to a vertical string L. When the string…

A:

Q: This, the length of the pendulum is 1.66 m. Now you start with the pendulum at 17.1 degrees with…

A: Solution:-Given thatLength of pendulum (L)=1.66 m

Q: The figure blow shows the kinetic energy of a simple pendulum versus its angle θ from the vertical.…

A: The change in kinetic energy = the change in potential energy  for θ  = 0  to  100  mrad  the change…

Q: A simple pendulum has a period of 4.1 s and an amplitude of 5.0 cm. The mass of the bob is 5 g.…

A:

Q: A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in…

A:

Q: Question 2, During a physics lab, Christina set up a pendulum that oscillated as shown below. When…

A: The total mechanical energy is the sum of kinetic and potential energy .

Q: A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in…

A:

Q: A block of mass m = 5 Kg is attached to a spring of spring constant k. The block ocillates in simple…

A: i) The transverse wave function is a function of both x (the undisplaced position of the point) and…

Q: A 1 kg object is attached to a spring and is oscillating on a horizontal surface. When the object…

A: mass of object (m) = 1 kg speed of object at an instant when elongation in spring in 0.4 m = 10 msg…

Q: A student releases the 4kg bob of a 1.9m long pendulum from the position shown. Neglect loss. What…

A:

Q: gy peno

A: Maximum kinetic energy of simple pendulum is KEmax = 1/2 m A2 w2 Angular frequency  w= 2π /T m =…

Q: Having successfully survived his first bungee jump, Ron is hanging at rest from the end of the…

A: Ron bounces up and down using the bungee cord. Hence it an application of Simple harmonic motion.…

Q: In a science museum, you may have seen a Foucault pendulum, which is used to demonstrate the…

A: Given Data: The mass of the pendulum is m=110 g.The length of the swings is L=15 m.The amplitude of…

Q: A 0.600 kg block is attached to the top of a vertical spring (with spring constant 78.4 N/m) and…

A: Given values: Mass of the block, m=0.600 kg Spring constant, k=78.4 N/m

Q: spring constant k

A:

Q: A block of mass m = 5 Kg is attached to a %3D spring of spring constant k. The block oscillates in…

A: Here, T =14.4 J mass(m)= 5 kg Now the energy  T = 1/2mv² So , 14.4= 5/2v² VMax = 2.4 m/s

Q: A block with mass 6.00 kg sliding on a horizontal frictionless surface is attached to one end of a…

A: Basic Details According to the conservation of energy, the energy of the system remains conserved.…

Q: This, the length of the pendulum is 2.16 m. Now you start with the pendulum at 30.5 degrees with…

A:

Q: A 5.00 kg partridge is suspended from a pear tree by an ideal spring of negligible mass. When the…

A:

Q: A 0.650 kg block is attached to a spring with spring constant 14.0 N/m. While the block is sitting…

A:

Q: is tied to a light string that has a length of 2.80 m. The end of the string is a vertical distance…

A:

Q: A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in…

A: Given: The mass is m=5 kg. The energy is E=22.5 J. The expression for maximum velocity is:…

Q: simple pendulum is suspended from the ceiling by means of a string of length  2.00 m. Now you start…

A:

Q: A 0.56 kg metal sphere oscillates at the end of a vertical spring. As the spring stretches from 0.12…

A: Given Data:The mass of the metal sphere is m=0.56 kgThe spring stretches from xi=0.12 m to xf=0.23…

Q: A block of mass m = 5 Kg is attached to a spring of spring constant k. The block ocillates in simple…

A: m= 5kg  total mechanical energy E= 22.5 J let maximum velocity be vmax

Q: A block of mass m = 5 Kgis attached to %3D a spring of spring constant k. The block oscillates in…

A: mass of block (m) = 5 kg spring constant = k Total energy (E) = 22.5 J

Q: what is its speed (in m/s) when it is a distance of 10 cm from the equilibrium position

A: If we apply conservation of energy  Then  Initiay energy = final energy Initial energy is for…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.