OK, once again we have a pendulum, this time of length 1.86 m, which you release from rest at an angle of 52.5 degrees to the vertical. What will be the speed of the pendulum at the instant it reaches an angle of 10.5 degrees above the vertical?     3.78 m/s     0.78 m/s     5.67 m/s     3.70 m/s

A mass m = 4.25 kg is at the end of a horizontal spring on a frictionless horizontal surface. The mass is oscillating with an amplitude A = 5.5 cm and a frequency f = 0.95 Hz.   Calculate the total mechanical energy E, in joules.  Equation to find energy is: E = 2π2 f2 m A2

7. The spring is compressed by the mass (m= 2 kg) to half of its original length and then released. The surface is not smooth and has coefficient of friction 0.2. What will be its speed after 2 s. The spring constant is 200 N/m and the unstretched length of the spring is 60 cm.The mass is not connected to the spring and it can slide on the surface after it is released after compression. k m x = 0

A horizontal spring attached to a wall has a force constant of 890 N/m. A block of mass 1.40 kg is attached to the spring and oscillates freely on a horizontal, frictionless surface as in the figure below. The initial goal of this problem is to find the velocity at the equilibrium point after the block is released. x= 0 (a) x= 0 PE, = KE= 0 (b) X=0 PE, = 0 !! (c) (a) What objects constitute the system, and through what forces do they interact? (b) What are the two points of interest? (c) Find the energy stored in the spring when the mass is stretched 5.00 cm from equilibrium and again when the mass passes through equilibrium after being released from rest. x = 5.00 X = 0 J (d) Write the conservation of energy equation for this situation and solve it for the speed of the mass as it passes equilibrium. (Do this on paper. Your instructor may ask you to turn in this work.) (e) Substitute to obtain a numerical value. m/s

A pendulum is created with a string of length L, fixed at the top. A ball with mass m is fastened to the bottom. The ball is pulled to the side through an angle theta anrd released. What is the speed of the ball at lowest point? L=1.90 Theta=29.0 Mass=600kg

A partridge of mass 5.01 kg is suspended from a pear tree by an ideal spring of negligible mass. When the partridge is pulled down 0.100 m below its equilibrium position and released, it vibrates with a period of 4.21 s. What is its speed as it passes through the equilibrium position? What is its speed as it passes through the equilibrium position? When it is moving upward, how much time is required for it to move from a point 0.050 m below its equilibrium position to a point 0.050 m above it?

QUESTION 3 This, the length of the pendulum is 1.03 m. Now you start with the pendulum at 28.7 degrees with respect to the vertical, but rather than releasing it from rest, you give it a push downward. It swings to the other side, and reaches a maximum angle of 47.8 degrees with respect to the vertical. What must have been the initial speed of the pendulum just after you pushed it?   A 2.04 m/s   B 2.58 m/s   C 1.58 m/s   D 3.61 m/s

A 1 kg block is attached to a spring with a constant of 100 N/m. The spring is displaced 0.1 m from equilibrium. When the block is let go, what is its velocity as it passes the equilibrium point? 4.0 m/s 0.4 m/s 1.6 m/s 2.0 m/s 1.0 m/s

This, the length of the pendulum is 1.89 m. Now you start with the pendulum at 8.5 degrees with respect to the vertical, but rather than releasing it from rest, you give it a push downward. It swings to the other side, and reaches a maximum angle of 42.5 degrees with respect to the vertical. What must have been the initial speed of the pendulum just after you pushed it?     4.99 m/s     3.06 m/s     3.12 m/s     0.64 m/s

3) OK, once again we have a pendulum, this time of length 1.94 m, which you release from rest at an angle of 59.1 degrees to the vertical. What will be the speed of the pendulum at the instant it reaches an angle of 29.6 degrees above the vertical? Question 2 options:   6.88 m/s   3.68 m/s   4.30 m/s   2.23 m/s 4) This, the length of the pendulum is 2.17 m. Now you start with the pendulum at 10.2 degrees with respect to the vertical, but rather than releasing it from rest, you give it a push downward. It swings to the other side, and reaches a maximum angle of 34.0 degrees with respect to the vertical. What must have been the initial speed of the pendulum just after you pushed it?   2.70 m/s   0.82 m/s   3.51 m/s   2.57 m/s