2.OIL FLOWS feomTHE PRESSULIRm TAMKAT A TO 8. DETERMIETHE PEFSSURE AT ATO CAUSE A FLOWOF 0.002 m/sEC0 = 20 mmAIR5 m2 mOIL5.6=0.9f= 0.02k = 0.56 mALL,MIL'sBEQSQ = VA1mP=dhM.2's = KU%g%3D- fr + Fp + £ +V.+2, =& +V ,2 29+ HeF29BA

Apply bernollis eqn. between A and B.for solution refer below images.

OIL FLOWS fRom THE PRESSULIRD TANK AT A TO 8, DETERMIN THE PesssURE AT A TO CAUSE A FLOW OF 0.002 An/sEC D = 20 mm AIR A 5 m 2 m S.6= 0.9 OIL f= 0.02 K. = 0.5 ALL, M.L's 6 m B 1m Q = VA %3D %3D Poth M.z's = KU/22 %3D -fr + Fp + 29 2 29 + He f BA

OIL FLOWS fRom THE PRESSULIRD TANK AT A TO 8, DETERMIN THE PesssURE AT A TO CAUSE A FLOW OF 0.002 An/sEC D = 20 mm AIR A 5 m 2 m S.6= 0.9 OIL f= 0.02 K. = 0.5 ALL, M.L's 6 m B 1m Q = VA %3D %3D Poth M.z's = KU/22 %3D -fr + Fp + 29 2 29 + He f BA

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Metrology of surface finish

In general terms, the application of scientific principles in the study of measurements is known as metrology. When speaking about measurement, it could be of time, length, microstructures, grain structures, internal crystal discontinuities, surface roughness, measurements of angles, height, width, and so on. While coming to the domain of mechanical engineering, metrology is considered the science of measurements of surface finish, length, surface texture, and angles.

Question

2.
OIL FLOWS feom
THE PRESSULIRm TAMK
AT A TO 8. DETERMIE
THE PEFSSURE AT A
TO CAUSE A FLOW
OF 0.002 m/sEC
0 = 20 mm
AIR
5 m
2 m
OIL
5.6=0.9
f= 0.02
k = 0.5
6 m
ALL,
MIL's
B
EQS
Q = VA
1m
P=dh
M.2's = KU%g
%3D
- fr + Fp + £ +V.+2, =& +V ,
2 29
+ HeF
29
BA

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