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Of the following alloys, pick the one(s) that
may be strengthened by heat treatment,
cold work, or both: R50250 titanium, AZ31B
magnesium, 6061 aluminum, C51000 phos-
phor bronze, lead, 6150 steel, 304 stainless
steel, and C17200 beryllium copper.
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- T or F -In the hypereutectoid steel alloy, the primary phase is Cementite ( iron carbide ) -In the Pb-Sn hypoeutectic alloy, the primary phase is the α-phase -The eutectic composition of the solder alloy is 98%wt Sn -In the steel alloys, the weight percent of the alloying elements affects the eutectoid temperature and Ceutectoid wt%C -Austenite phase has a BCC crystal structure The microstructure is characterized by: a.The number of phases present b.The present phases’ proportions. c.How these phases are arranged or distributed d.all of the answersWhat is the composition (wt% C) of a steel with AISI designation 1090? .Would this be considered a low, medium, or high carbon steel? (circle one)Answer with true (T) or false (F), corrects the wrong phrases, and gives short reason(s) for correct and corrected statements: 1- Normalized steels have better strength and toughness as compared to annealed steels. 2- Ferrous alloys are most important and widely used in comparison to any other metals. 3- Metals of BCC crystal structure are denser than metals of FCC structure. 4- Hypo-eutectoid steels fully annealed by heating to about 30°C above the upper critical temperature. X A3 5- The full martensite microstructure can be obtained by cooling the steels with any cooling rate. 6- There is a large volume expansion when martensite forms from austenite.,
- Answer with true (T) or false (F), corrects the wrong phrases, and gives short reason(s) for correct and corrected statements: 1- Normalized steels have better strength and toughness as compared to annealed steels. 2- Ferrous alloys are most important and widely used in comparison to any other metals. 3- Metals of BCC crystal structure are denser than metals of FCC structure. 4- Hypo-eutectoid steels fully annealed by heating to about 30°C above the upper critical temperature. 5- The full martensite microstructure can be obtained by cooling the steels with any cooling rate. 6- There is a large volume expansion when martensite forms from austenite.Answer with true (T) or false (F), corrects the wrong phrases, and gives short reason(s) for correct and corrected statements: 1- Normalized steels have better strength and toughness as compared to annealed steels. 2- Ferrous alloys are most important and widely used in comparison to any other metals. 3- Metals of BCC crystal structure are denser than metals of FCC structure. 4- Hypo-eutectoid steels fully annealed by heating to about 30°C above the upper critical temperature.X A3 5- The full martensite microstructure can be obtained by cooling the steels with any cooling rate. 6- There is a large volume expansion when martensite forms from austenite.,The TTT diagram for a 1076 eutectoid steel is given: What is the heat treatment process to form 50% Coarse Pearlite + 50% Martensite. 800 A 1400 Eutectoid temperature 700 A 1200 600 1000 500 800 400 A 600 300 M(start) 200 50% 400 M + A M(50%) M(90%) 100 200 10-1 1 10 102 103 104 105 Time (s) Temperature (°C) Temperature (°F)
- How do ferrite and cementite work together to form a strong ductile steel?As an R&D engineer, your input is requested to design an enhanced device that will be permanently implanted to repair the load-bearing function of a joint. Details on the candidate metals are presented here: Material SS 316 type Pure Ti Density (p) Yield stress (g/cm³) (MPa) 8 4.5 Ti6A14V 4 (F136) 190 140 795 Maximum elongation (%) 40 15 10 Elastic modulus (GPa) 190 110 114 Lo Shess leve O What force can each of the materials carry without permanent deformation? Which one offers better properties as a load-bearing implant? Explain. Describe the primary consequences of choosing the wrong material; consider in your answer the effect of density, yield stress, elongation, and Young's modulus on the implant's performance.1 Plastic Deformation Occurs Through Dislocation Motion... ...so in order to make a material stronger, we should prevent dislocations from moving. For each of the following alloys, identify the strengthening mechanism and explain how it impedes dislocation motion: A. An aluminum alloy "inoculated" with TiB2 during solidification, producing a large number of small grains. B. Monel, a corrosion-resistant solid solution of Ni and Cu. C. An aluminum-lithium aerospace alloy containing precipitates of Al3Li. D. Wrought iron, which is often worked into complex shapes such as railings or furniture.
- Copper and copper alloys as specified by the Copper Development Association (CDA) and are designated as C00001 thru C99999 in the Unified Numbering System (UNS). True False An alloy steel designated as AISI 4130 WQT 700 means: chromium-molybdenum alloy steel containing .30% carbon in solution, that is through heat treated and water quenched. True False An AISI 4340 alloy steel contains .43 percent or 43 points of the element carbon in solution. True False Chemicals from which the commercially important plastic resins are derived are themselves derived from natural products that are quite plentiful; these raw materials include coal, water, limestone, sulfur, salt, and petroleum. True False There are two (2) types of polymerization; addition or linear and cross-linked or condensation. Addition polymers are thermoplastics and cross-linked polymers are thermosetting materials. True FalseDraw Iron - Iron Carbide Phase diagram and show the following: 1- Temperature, phases and carbon weight for Eutectic. 2- Temperature, phases and carbon weight for Eutectoid Thecementite, 3- austenite, ferrite, delta phases with their 4- Types of ferrous alloys on different carbon rates. 5- Draw the phase at T= 700 CD and 0.7 wt% C what is its name ? temperatures and carbon weight.Q3: With a moderately agitated water, a cylindrical piece of steel with 80 mm diameter is to be quenched. The hardnesses of the surface and center must be at least 55 and 40 HRC, respectively. Which of these alloys will satisfy the following requirements: 1040, 5140, 4340, 4140, 8620, 8630, 8640, and 8660? Cooling rate at 700c Cooling rate at 700°c 170 70 31 18 5.6 3.9 "C 270 170 70 31 18 9 60 2 "Os 5.6 3.9 2.8 100 100 50 4340 80 75 3 Surface 40 4140 Center 8640 30 5140 25 1040 20 10 20 30 40 50 mm 10 20 30 mm Distance from quenched end Equivalent distance from quenched end Figure 3 Figure 4 Hardness, HRC Percent martensite Diameter of bar (mm)