of Let Q represent a mass radioactive plutonium (239pu) (in grams), whose half-life is 24,100. The quantity of plutonium present after t years. is Q = 18 (2/2) + / 24,100 a.) Determine the initial quantity (when +=0). g b.) Determine the guany present after 55.000 yours. (Round your to two decimal places.) answer -g

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Please help me, I can't seem to figure it out and it is due in 25 minutes. Someone, please help me ASAP! Thank you!

I only need answers to parts (b) (f) (g)

Let (n) = n H 2 (n+1) then solve the equation for n & (24(n)) = 2

Question 9 Chapter 1/Math Review Arrange this quadratic equation in standar (2z)² 23 (5-z)

Section 2.2 2.1. Solve the following difference equations: (a) Yk+1+Yk = 2+ k, (b) Yk+1 – 2Yk k3, (c) Yk+1 – 3 (d) Yk+1 – Yk = 1/k(k+ 1), (e) Yk+1+ Yk = 1/k(k+ 1), (f) (k + 2)yk+1 – (k+1)yk = 5+ 2* – k2, (g) Yk+1+ Yk = k +2 · 3k, (h) Yk+1 Yk 0, Yk = ke*, (i) Yk+1 Bak? Yk (j) Yk+1 ayk = cos(bk), (k) Yk+1 + Yk = (-1)k, (1) - * = k. Yk+1 k+1

For this problem how did they went from: 1.3.5...(2n+1) to 1.3.5....(2n-1)(2n+1) for finding an+1 ?

11.4 Converting from One Uni PROBLEMS FOR SECTION 11.4 1. A recipe calls for 4 ounces of chocolate. If you make 15 batches of the recipe (for a large party), then how many pounds of chocolate will you need? a. Use multiplication or division or both to solve the chocolate problem. Explain why your method of solution makes sense in a way that children could understand. Do not use di- mensional analysis. b. Describe a number of different correct ways to write the answer to the chocolate problem. Explain briefly why these different ways of writing the answer mean the same thing. b. A car is 41 feet and in centimete your reas 7. The distan 260 kilom Make an ing brief fact tha your an your a answe than 2. A class needs 27 pieces of ribbon, each piece 2 feet, 3 inches long. How many yards of ribbon does the class need? a. Use multiplication or division or both to solve the ribbon problem. Explain why your nkes sense in a way that 8. In Ge hour they firs late 9.0 fo

Question 11 The equation x+y -2x + 6y + 3 = 0 is equivalent to A (x-1)2 + (y + 3) = -3 (r+1)2 + (y +3)2 = 7 B (x-1)2 +(y+ 3)2 = 7 Ox+1) + (y + 3)2 = 10