of address (676)8 with primary partition (four 16 bytes en
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What is the size in octal of MBR of address (676)8 with primary partition (four 16 bytes entries)?
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- What are the benefits of segmented memory address translation over a straight translation?Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a cache size of 512 bytes, and each cache block contains 64 bytes.Q.) What is the format of a memory address as seen by cache; that is, what are the sizes of the tag, block, and offset fields?How many address bits are required for a 2048-bit memory organized as a 256 * 8 memory?
- What are the advantages of segmented memory address translation over straight translation?Suppose a computer using direct-mapped cache has 2 bytes of byte-addressable main memory and a cache of 32 blocks, where each cache block contains 16 bytes.Q.) What is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, block, and offset fields?Consider a 4096 * 8 RAM in which the last 64 addresses are used as a LIFO stack. If the first address in the RAM is 00016, designate the 64 addresses used for the stack.
- Suppose a computer using fully associative cache has 216 bytes of byte-addressable main memory and a cache of 64 blocks, where each cache block contains 32 bytes.Q.) What is the format of a memory address as seen by the cache; that is, what are the sizes of the tag and offset fields?Design a memory map to work with 8085 Microprocessor to have 8K byte ROM and 2K byte RAM. ROM should start from memory location 0000H and RAM immediately follows it. Use exhaustive decoding scheme?What is the maximum number of 16-bit words that can be stored in a 2^32 byte physical memory?
- Consider the following table that represents part of the memory of a 16-bit address space that has an addressability of 2 bytes (like LC-3): ADDRESS OxFFFF OXOCOE OXOCOD Ox0C0C OXOCOB OXOCOA 0x0C09 0x0000 CONTENTS 1111 1111 1111 1111 1111 1110 1101 1100 0001 1011 1100 0101 0110 0101 1000 0111 1100 0000 0100 0000 0011 0001 0101 0010 0000 1100 0000 1101 0000 0000 0000 0000 The table above shows the addresses in hex (base 16) and the contents at the corresponding address in binary (base 2). A.) What are the contents in hex of the memory location at following address in binary: 0000 1100 0000 1110? (Enter hex like the following example: Ox2A3F)Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a cache of 128 blocks, where each block contains 64 bytes.Q.) What is the format of a memory address as seen by cache; that is, what are the sizes of the tag and offset fields?Consider the array : char arr[5]; If address of arr is 100 then what will be the address of arr[4]. Given each char occupies 1 byte in a byte addressable system.
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