Of 54 bank customers depositing a check, 17 recelved some cash back. (a) Construct a 90 percent confidence Interval for the proportion of all depositors who ask for cash back. (Round your answers to 4 decimal places.) The 90% confidence interval is from to (b) May normality of p be assumed? O Yes O No

Q: A 90% confidence interval for the proportion of coffee drinkers that add sugar and creme has results…

A:

Q: random survey of 500 students was conducted from a population of 2,300 students to estimate the…

A: We have given that n=500, X=245 90% confidence interval

Q: In a past general social survey 87 percent of a random sample of n=990 respondents answered yes to…

A:

Q: 45 Bank customers depositing a check, 21 received some cash back. a. Construct a 90% confidence…

A: Given that: Sample size (n) = 45  X represents received some cash back. X = 21 At 90 % confidence…

Q: d) Compute the 95% confidence interval for “pcol”.   e.)  Do the results from your confidence…

A: The 95% CI is given by ​​​​​​​

Q: Out of 200 people sampled, 168 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: Construct both a 90% and a 80% confidence interval for B1. B, = 44, s = 4.7, SS= 43, n = 12 90% :…

A: Obtain the 90% confidence interval for slope. The 90% confidence interval for slope is obtained…

Q: Of 41 bank customers depositing a check, 15 received some cash back.   (a) Construct a 90 percent…

A: It is given that sample size (n) is 41 and the number of depositors received some cash back (x) is…

Q: xpress the confidence interval (48.1% , 64.7%) in the form of (p-hat) +- ME ______%+-______%.…

A: Given Information: Confidence interval for population proportion p is: (48.1% , 64.7%) = (0.481,…

Q: Out of 600 people sampled, 402 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: The 95% confidence interval of the average monthly bill for female is between 72.9334 and 0.61.5466.

A: The confidence interval is the interval range in which represent true value within it. It is…

Q: In a survey of 2000 American adults age 60 and over, 1320 received a flu shot. Construct a 90%…

A: Given that,X =  1320N = 2000

Q: Of 41 bank customers depositing a check, 15 received some cash back. (a) Construct a 90 percent…

A: Given data, n=41 x=15 p=x/n =15/41 =0.3659 z-value at 90% confidence is Zc=1.645

Q: 21 % of the 100 students in Emmie Xi Hem International School students said that they had been late…

A: given data p^ = 0.21sample size n = 100

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: A random sample of 5001 adults in a country includes 755 who do not use the Internet. Construct a…

A:

Q: Of 44 bank customers depositing a check, 23 received some cash back. (a) Construct a 90 percent…

A: a)Here, n=44 x=23

Q: 11 % of the 100 students in Emmie Xi Hem International School students said that they had been late…

A:

Q: Out of all the students that attend Yale University, 1,982 were selected to participate in a school…

A:

Q: A history teacher records the SAT scores of all 87 of her students. The data is used to construct a…

A: For calculating the confidence interval, we need to satisfy the following conditions: Independence…

Q: Of 40 bank customers depositing a check, 17 received some cash back.   (a) Construct a 90 percent…

A: From the provided information Sample size (n) = 40, x = 17 The sample proportion can be obtained as:

Q: A newsgroup is interested in constructing a 90% confidence interval for the proportion of all…

A: Consider, Number of Americans surveyed (n) = 555 Number of Americans that are in favor of the…

Q: The Athletics Department at a high school is interested in the difference in the run times between…

A: The given 95% confidence interval is -0.6,3.1.

Q: Of 54 bank customers depositing a check, 23 received some cash back.   (a) Construct a 90 percent…

A: Given that, out of 54 bank customers depositing a check, 23 received some cash back.

Q: Let p₁ be the proportion of students in English class who receive grade A, and p2 be the proportion…

A: Given,the sample proportions of Grade A in English class and Maths class.To choose the correct…

Q: Of 58 bank customers depositing a check, 15 received some cashback. a.) Construct a 90 percent…

A: Solution: a. Let X be the number of depositors ask for cash back and n be the sample number of bank…

Q: None

A:

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Confidence intervals is an inference process which can be used to estimate the population parameter.…

Q: 34% of the 100 students in Emmie Xi Hem International School students said that they had been late…

A: We have given that  Sample size n =100 Sample proportion p^=34%=0.34 99% confidence interval.

Q: A university admissions person claims that more than 70% of its students graduate within four years.…

A: Given that  A university admissions person claims that more than 70% of its students graduate within…

Q: Construct the 90% confidence interval for the difference p1-p2 when x1=45, n1=85, x2=20, and n2=65.…

A: Given Information: x1=45n1=85x2=20n2=65c=90%=0.90

Q: Of 45 bank customers depositing a check, 21 received some cash back.   (a) Construct a 90 percent…

A: Solution: a. Let X be the number bank customers received some cash back and n be the sample number…

Q: (c) In a random sample of visitors to a famous tourist attraction, 252 of 750 American tourists and…

A: We have given that,  X1 = 252, n1 = 750 and X2 = 312, n2 = 500 Then,  We will find 96% confidence…

Q: Based on a random sample of 50 students, the 90 percent confidence interval for the mean amount of…

A: From the provided information,Sampe size (n) = 5090% confidence interval is found to be ($3.45,…

Q: Out of 600 people sampled, 456 had kids. Based on this, construct a 95% confidence interval for the…

A: According to the given information, we have Total number of people sampled = 600 Out of 600 people…

Q: Of 41 customers depositing a check, 20 received some cash.  a. Construct a 90 percent confidence…

A: Given,n=41x=20p^=xnp^=2041=0.48781-p^=1-0.4878=0.5122α=1-0.90=0.1α2=0.05Z0.05=1.645   (from Z-table)

Q: A survey of randomly selected university students found that 92 of the 107 first-year students and…

A: (a)   Obtain the 99% confidence interval for the difference in the proportions of first-year and…

Q: A random sample of 500 patients with diabetes were weighed before and after switching to a new drug…

A: The objective of the question is to determine the 95% confidence interval for the average change in…

Q: A survey of randomly selected university students found that 95 of the 100 first-year students and…

A: (a) Obtain the 95% confidence interval estimate for the difference in the proportions of first year…

Q: wsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans…

A: given data, CI=0.95α=1-0.95=0.05n=504x=448p^=xn  =448504  =0.8888

Q: Each man in a random sample of n = 16 men between 30 and 39 years old is asked to do as many sit-ups…

A: We have given that,  Sample mean (x̄) = 24.2, standard deviation    (s) = 8 and sample size (n) = 16…

Q: At a traffic stop on a Saturday night 30% of 40 drivers were intoxicated. What is the 99% confidence…

A: