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- Multiply left and right array sum. Basic Accuracy: 54.29% Submissions: 12630 Points: 1 Pitsy needs help in the given task by her teacher. The task is to divide a array into two sub array (left and right) containing n/2 elements each and do the sum of the subarrays and then multiply both the subarrays. Example 1: â€Create an ABM function that takes the following parameters: n := number of paths to be simulated m := number of discretization points per path S0 := initial starting point dS=μdt+σdW Program the function by using two nested "for loops" def ABM(n,m,S0,mu,sigma,dt): np.random.seed(999) arr = # create 2D zeros array with the correct dimensions arr[,] = #initialize column 0 # fill in array entries for i in : for j in : arr[i,j] = return arrGiven an integer array Arr of size N the task is to find the count of elements whose value is greater than all of its prior elements. Note : 1st element of the array should be considered in the count of the result. For example, Arr={7,4,8,2,9} As 7 is the first element, it will consider in the result. 8 and 9 are also the elements that are greater than all of its previous elements. Since total of 3 elements is present in the array that meets the condition. Hence the output = 3.Function PrintArray(integer array(?) dataList) returns nothing integer i for i = 0; i < dataList.size; i = i + 1 dataList[i] = Get next input Put dataList to output Put "_" to output // Your solution goes here. Modify as needed i = 0 Complete the PrintArray function to iterate over each element in dataList. Each iteration should put the element to output. Then, put "_" to output. Ex: If dataList's elements are 2 4 7, then output is: 2_4_7_ Function Main() returns nothing integer array(3) userNums integer i for i = 0; i < userNums.size; i = i + 1 userNums[i] = Get next input PrintArray(userNums)9.). integer array nums and an integer k, return the length of the shortest non-empty subarray of nums with a sum of at least k. If there is no such subarray, return -1. A subarray is a contiguous part of an array. Example 1: Input: nums = [1], k = 1 Output: 1 Example 2: Input: nums = [1,2], k = 4 Output: -1 Example 3: Input: nums = [2,-1,2], k = 3 Output: 3.Select the for-loop which iterates through all even index values of an array.A. for(int idx = 0; idx < length; idx++)B. for(int idx = 0; idx < length; idx%2)C. for(int idx = 0; idx < length; idx+2)D. for(int idx = 0; idx < length; idx=idx+2)In main() for now: do these - one at a time, each in it's own loop (we will make functions out of them later –Declare an array RandArray with 20 integers –Assign each of the 20 values with a random value from 0 to 99 Hint: Use rand()%100 For mimir: Do not call srand at the top of main. // normally: Call srand(time(0)) at the top of main –(you need #include<cstdlib>) –Write another loop that prints the array, with index values Important: If the output values do not match mimir, please add srand(17); // inside your main function - at the top code format: #include <iostream>using namespace std; #include <cstdlib> // required for rand() int main(){ srand(17); // define a constant ARRAYSIZE that is 20 // declare randArray // set the 20 elements in randArray to be a random number between 0 and 99 // hint: use rand()%100 // print the 20 values return 0;}“A” array has a members and “B” array has b members which are sorted. I need an algorithm to find the k-th member in a new array which is a mix of “A” and “B”. The runtime must be O(log(a+b))Java Program Your program should use 2D arrays to implement simple matrix operations. Your program should do the following: • Read the number of rows and columns of a matrix M1 from the user. Use an input validation loop to make sure the values are greater than 0. • Read the elements of M1 in row major order • Print M1 to the console; make sure you format as a matirx • Repeat the previous steps for a second matrix M2 • Create a matrix M3 that is the transpose of M1 and print it to the console • Check if M1 and M2 can be added (should have the same dimensions). If possible, add M1 and M2 and print the result to the console. Otherwise print an error message. • Extra credit: Multiply M1 and M2 if possible and print to the console. If the matrices cannot be multiplied, print an error message. Implementation requirements: • Use a helper method for reading a positive integer using an input validation loop. • Use a helper method for printing a matrix. Your helper methods should be private and…An array is special if every even index contains an even number and every odd index contains an odd number. Create a function that returns true if an array is special, and false otherwise. Examples isSpecialArray([2, 7, 4, 9, 6, 1, 6, 3]) → true // Even indices: [2, 4, 6, 6]; Odd indices: [7, 9, 1, 3] isSpecialArray([2, 7, 9, 1, 6, 1, 6, 3]) → false // Index 2 has an odd number 9. isSpecialArray ([2, 7, 8, 8, 6, 1, 6, 3]) → false // Index 3 has an even number 8.01... ""Implementation of the Misra-Gries algorithm.Given a list of items and a value k, it returns the every item in the listthat appears at least n/k times, where n is the length of the array By default, k is set to 2, solving the majority problem. For the majority problem, this algorithm only guarantees that if there isan element that appears more than n/2 times, it will be outputed. If thereis no such element, any arbitrary element is returned by the algorithm.Therefore, we need to iterate through again at the end. But since we have filtredout the suspects, the memory complexity is significantly lower thanit would be to create counter for every element in the list. For example:Input misras_gries([1,4,4,4,5,4,4])Output {'4':5}Input misras_gries([0,0,0,1,1,1,1])Output {'1':4}Input misras_gries([0,0,0,0,1,1,1,2,2],3)Output {'0':4,'1':3}Input misras_gries([0,0,0,1,1,1]Output None"""..I'm stuck on this question and I don't know how I should be approaching this. What should I do? Question: ------------------ Solving the N-Queens Problem Main Function Create a one-dimensional array of size n and seed it with -1 values. This represents an empty n x n chess board. Develop the problem with n=4, test the solution up to n=24. Note that the array index represents the row, and array value the column. Print Function Print the array where all -1 values are empty spots on the board and all values not equal to -1 represent the position of a queen. isSafePosition Test if a specific row/col position is safe for a queen relative to all previous rows (row-1). If placing a queen into this specific row/col position would be dangerous return false, else return true. Solve Use backtracking to provide a solution for the current board size. This is a recursive function which repeatedly tests different queen layouts until it ultimately finds a working solution. Your…SEE MORE QUESTIONS