Obtain the gradient to a curve with the parametric equations given by I = In - and y = sinh 2t whent = 1. TMOUTM

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Q: 3. Find the equation of the tangent line and the normal line of parametric equa- tions for a curve x…

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Q: Find the equation of the tangent line of the curve y = sin r + cos a at the point A(, v2).

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Q: B) Find an equation of the tangent line to the curve at the given point y = (1+ Vx)³ at x =1 ?

A: Given curve is, y=(1+x3 )3 at x=1.  The objective is to find the equation of the tangent.     For…

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Q: Which equation describes the tangent line to the curve * (t) = > at = 0₁ e³t. To(x) = To(u) = u…

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Q: For the curve r-y +2xy-y+1=0: a) Find the derivative dy/dx. b) Where do the horizontal tangent lines…

A: follow the next step

Q: A particle moves along the same path as in question (4) where the path is d scribed by the…

A: To find the acceleration components normal and tangential to the path at t=2 seconds and the radius…

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Q: Given smooth parametric curve y = |(16t² - 4 3 151²³. where t E R \ 48t + 35 5 7 (7) x = t³-t²- 2t,…

A: As per the question we are given the parametric equation of a curve x(t), y(t) And we have to :…

Q: Find the tangent line(s) to the parametric curve given by a = t¹ - 9t² and y=t² at (0, 9).

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Q: A mouse Q runs along the positive y-axis at the constant speed v at the origin. A cat P chases the…

A: It is given that∙Mouse Q runs along y-axis with a constant velocity v1∙Cat P runs along curve C with…

Q: 11. Find the slope of the tangent line t = 2. Show all your worka x = v2t, y =t %3D t

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Q: Find the equation of the curve at any point  P(x,y) of a curve the subtangent equals -1/x

A: Given that the subtangent equals -1x. Then we get, tan θ2=-1x⇒tan θ=2 tan θ21-tan2 θ2⇒tan…

Q: 3. For the curve x – xy² = 8e²4, do the following | a) Verify that the point (2,0) is on this curve.

A: Given, curve x3-xy2=8e2y

Q: 1.. Plot the cardioid curve (0)=2+2 sin then compute all angles for which the slope of the tangent…

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Q: classify by type, order and linearity the following equation (1-x)y"-8xy'+6=cosx

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