Observe the following code and answer the following questions. import java.io.*; import java.net.*; import java.util.Date; public class TimeServer{ public static void main(String args[]) throws Exception{ ServerSocket server = new ServerSocket(9876); while (true){ Socket client = server.accept(); //blocks until a client connects PrintStream ps = new PrintStream( client.getOutputStream() ); ps.println("Time from server:" + new Date()); client.close(); } } }     What type of server this is? Is it single or multi-threaded?                                                                         2. What should be done according to you if the number of clients to this server increases? Modify the server code so that the increases number of clients can be handled by this server.                                                                                                           3. Explain where in your code you ensured that for every incoming request from a client, a new thread is created to serve that client

For the following code I get an error:      Exception in thread "main" java.lang.Error: Unresolved compilation problems:      The type LinkedListIn is not generic; it cannot be parameterized with arguments <String>      The type LinkedListIn is not generic; it cannot be parameterized with arguments <>        at linkedList.LinkedListTester.main(LinkedListTester.java:5) How can I fix it? package linkedList;   public class LinkedListTester { public static void main(String[] args) { LinkedListIn<String> list = new LinkedListIn<>(); list.display(); list.add("Station 1"); list.add("Station 2"); list.add("Station 3"); list.add("Station 4");   // Print the linked list System.out.println("All Stations: " + list); // Accessing the first item System.out.println("First stop: " + list.getFirst()); // Accessing the last item System.out.println("Last stop: " + list.getLast()); // Removing the first item System.out.println("Left this station: " + list.removeFirst()); //…

Solution question number 2

Consider the below Java code. import public class Semaphore Demo java.util.concurrent.Semaphore; Semaphore binarySema= new Semaphore (1); public static void main (String args[]) { final SemaphoreDemo sema DemoObj= new Semaphore Demo (); Thread td1= new Thread() ( public void run () { } }} } }; Thread td2= new Thread () { @Override public void run () { sema DemoObj.testMutualExclusion (); } sema DemoObj.testMutualExclusion (); tdl.start(); td2.start (); private void testMutualExclusion () { try { binarySema.acquire(); System.out.println (Thread.currentThread().getName()+ "inside the region of mutual exclusive."); Thread.sleep (1000); } catch (InterruptedException e) { ie.printStackTrace(); } finally ( System.out.println (Thread.currentThread().getName() + "outside the region of mutual exclusive."); What would be the output of the program?

Steps to be followed: Create a class called MyThread that extends the Thread class. Declare an instance variable int limitToStop in the MyThread class. Create a parameterized constructor in the MyThread class that takes an int as a parameter to initialize a limitToStop instance variable. Override the run() method in the MyThread class. In the run() method, put a for-loop that goes from 0 to limitToStop. The block associated with the for-loop should print out only the odd numbers. Call Thread.sleep(1000) after every number you print out in the for-loop you created in the previous step. The Thread.sleep(1000) method throws an InterruptedException , which is a checked exception. Therefore, we need to enclose the Thread.sleep(1000) call in a try block. Also, add a catch block associated with the try that catches the InterruptedException and prints out the exception information using the printStackTrace() method. Create a MyThread variable using the new keyword in the main()…