Objective: Explain and employ network addressing. For all of the columns below use the IP address: 175.30.101.205 Instructions: 1. The first 3 columns are different ways of viewing the subnet mask. You are given the subnet mask as one of the 3, and you need to complete the other two representations for each row. Complete these 3 columns first. 2 3 1/28 5 6 4 /30 2. Proceed to complete the Increment by determining the value of the last network bit for the given subnet mask. It is easiest to observe in the binary representation. 8 3. Since network IDs will always be multiples of the increment (after the zero subnet) - in the octet that holds the last network bit, use the increment to determine the network ID, broadcast, given the subnet mask for that row. and host range for the IP address displayed above, Slash Notation 9 7 122 Network+ Learning Activity #23 - Subnet Masks and Subnetting 10 /21 Binary Subnet Mask 11111111 111111.11111111.11100000 11111111 11111111.11111111.1100000000000000 111110.00000000 Dotted Decimal Subnet Mask 255.255.255.192 255.255.240.0 255.255.224.0 Increment Network Broadcast Host Range

The message to be sent from source to destination is 4000B.  The link MTU's from source to destination are 1500, 1000, and 750. If we  DO NOT use Path MTU, what are the respective fragment sizes to be reassembled? If we DO use Path MTU, what are the respective fragment sizes to be reassembled? Remember, assume that the L3 and L4 headers have length=0.

Suppose within your web browser you click on a link to obtain a Web page. The IP address for the associated URL is not cached in your local host, so a DNS lookup is necessary to obtain the IP address. Suppose that three DNS servers are visited before your host receives the IP address from DNS. The first DNS server visited is the local DNS cache, with an RTT delay of RTT = 4 msecs. The second and third DNS servers contacted have RTTs of 45 and 24 msecs, respectively. Initially, let's suppose that the Web page associated with the link contains exactly one object, consisting of a small amount of HTML text. Suppose the RTT between the local host and the Web server containing the object is RTTHTTP = 9 msecs. Assuming zero transmission time for the HTML object, how much time elapses from when the client clicks on the link until the client receives the object? (Do not forget the TCP handshake(s).) 82 msecs O 91 msecs O 46 msecs O 67 msecs

SMTP (Simple Mail Transfer Protocol) is the standard protocol for transferring mail between hosts. A TCP connection is set up between a user agent and a server program. The server listens on TCP port 25 for incoming connection requests. The user end of the connection is on a TCP port number above 1023. You have defined the packet filter rule set shown in the table below. These rules permit and/or deny inbound and outbound traffic between the user agent and the mail server. Describe the purpose of each packet filter rule in the table.  Rule Direction Source Address Destination Address Protocol Destination Port Action A2 In External Internal TCP 25 Permit B2 Out Internal External TCP > 1023 Permit C2 Out Internal External TCP 25 Permit D2 In External Internal TCP > 1023 Permit E2 Either Any Any Any Any Deny

Q1: The following is a dump of a UDP header in binary form 0100 0001 0010 0011 0100 0001 0010 0111 0000 0000 0010 1111 0100 0001 0011 1111 Find in decimal form the following: (a) Source port number (b) Destination port number (c) Total length of the UDP (d) Length of the data (e) Check sum. (5 Marks)

A portion of the header of a UDP segment is captured as 8-bit hexadecimal numbers as shown below. 00 35 D2 71 00 86 For this UDP header, the checksum in hexadecimal is Ox[a] and the length of the UDP segment in decimal is [b]. Note: do not include 'Ox' in your first answer.

Consider an IP packet with a length of 4,500bytes that includes a 20-byteIPv4 header ans 40-byte TCP header. The packet is forwarded to an IPv4 router that supports a Maximum Transmission Unit (MTU) of 600bytes. Assume that the length of the IP header in all the outgoing fragments of this packet is 20bytes. Assume that the fragmentation offset value stored in the first fragment is 0. The fragmentation offset value stored in the third fragment is

IKT204-G H21, Routing tables 13 In this assignment, the objective is to determine the correct forwarding link given the routing table below. A router has the following entries in its forwarding table: Link1: 00001010.10101000.00000100.00000000/22 Link2: 00001010.10101000.00000110.00000000/23 Link3: 00001010.10101000.00000111.00000000/24 Link4: 00001010.10101000.00000000.00000000/16 Link5: All other addresses Assume the router receives IPV4 datagrams destined to the following addresses and decide which link they are forwarded to: A: 00001010.11111000.00000101.00001111 B: 00001010.10101000.00000111.00011000 C: 00001010.10101000.00000011.01010000 D: 00001010.10101000.00000111.11111110 E: 00001010.10101000.00000110.10000010 On which link will they be forwarded? A: link B: link C: link D: link E: link

• IPV6 addresses use 128 bits to represent an address which includes bits to be used for subnetting. The second half of the address (least significant 64 bits) is always used for hosts only. Therefore, there is no compromise if we subnet the network. Use the Figure below to Create five subnets using route prefix 2001:db:acad::/48 (1 Marks) Routing Prefix Subnet ID Interface ID 48 Bits 16 Bits 64 Bits

The first portion of IPv4 header of an FTP datagram packet is shown below. Offset 0 4 Header Data 0x48007000 OxA0120000 If the datagram was received by a router that is connected to a network with maximum transmit unit (MTU) = 0x3000. Show the headers of the resulting fragments transmitted by the router. Hint: 1) The first few fragments will have total length = MTU. 2) Fragmentation offset refers to datagram payload, not the fragment Fragmento Offset Header Data 0 4 Offset 0 4 Fragment1 Header Data Blank # 1 Fragment2 Offset Header Data 0 4 Blank1 Blank2 Blank # 3 Blank # 4 Blank # 2 Blank # 5 Blank3 Blank4 Blank # 6 Blank5 Blank6 N A A/ A/