Object 1 is located at (0,1.4) m and has a mass of 79 kg.  Object 2 is located at (9.4,4.1) m and has a mass of 79.9 kg.  Object 3 is located at (0.1,1.4) m and has a mass of 54.4 kg.  What is the x-coordinate of the center of mass of this three mass system?

A rod of length 39.00 cm has linear density (mass per length) given by ? = 50.0 + 21.0x   where x is the distance from one end, and ? is measured in grams/meter. (a) What is its mass?g(b) How far from the x = 0 end is its center of mass?m

Four beads, each of mass m = 1 kg, are attached at various locations to a ring, also of mass m = 1 kg, and radius M R = 1 m (see figure). Find the coordinates of the center of mass of the system consisting of the ring and the beads. Angle A, located between the first bead and the horizontal, m, m, R is equal to 41°. Angle B, located between the horizontal and the second bead, is equal to 50°. Angle C, located between the third bead and the horizontal, is equal to 72°. Angle D, located between the horizontal and the fourth bead, is equal to 31°. B Xem = m, Yem = about us careers privacy policy terms of use contact us help

The vector position of a 3.30 g particle moving in the xy plane varies in time according to r, = (3î + 3j)t + 2jt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g particle varies as r, = 3î – 2ît? – 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 3.00 s. cm "cm %3D (b) Determine the linear momentum (ing· cm/s) of the system at t = 3.00 s. g· cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 3.00 s. cm/s %3D cm (d) Determine the acceleration (in cm/s²) of the center of mass at t = 3.00 s. cm/s2 cm (e) Determine the net force (in µN) exerted on the two-particle system at t = 3.00 s. Fnet UN

A student sets up a coordinate system and observes person A is standing at (0 m, 0 m), person B stands at (x m, 0 m), and person C is standing at (0 m, y m). The masses of person A, B, and C are A=60.1 kg, B=70.4 kg, and C= 84.9 kg. Where is the center of all three people? a- (0.327 x; 0.394 y) m b- (0.279 x; 0.327 y) m c- (0.279 x; 0.394 y) m d- (0.327 x; 0.327 y) m e- (0.394 x; 0.394 y) m

The vector position of a 3.75 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r 31 – 2ît² – 6ĵt. r2 (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.80 s. cm = (b) Determine the linear momentum (in g· cm/s) of the system at t = 2.80 s. cm cm (c) Determine the velocity (in cm/s) of the center of mass at t = 2.80 s. cm g.cm/s net (d) Determine the acceleration (in cm/s²) of the center of mass at t = 2.80 s. cm/s² = = cm/s (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.80 s. μN

Three solid, uniform boxes are aligned as in the figure below. Find the x- and y-coordinates (in m) of the center of mass of the three boxes, measured from the bottom left corner of box A. (Consider the three-box system.) HINT Xcm Y cm = Origin 0.300 m m m A 0.700 kg 0.350 m B 1.00 kg 0.150 m 0.450 kg L. 0.418 m

Example B: Three people stand around not doing their physics homework as shown below. Find the distance of the center of mass of the 3 person system from leftmost person. M₁= 70 kg 4 m M₂=60 kg 6 m M₂= 82 kg

In the figure below, the masses of each object are: m₁ 1.00 kg, m₂ = 4.00 kg, m² = 6.00 kg. The labeled distances are: d₁ = 25.0 cm, d₂ = 104 cm, d3 = 60.0 cm (where d is the x distance for the center of the block). The height of each block is h₁ = 19.0,h₂ = 28.0 cm, and the h3 = 12.0 cm. Assume the center of mass for each individual object is at the center of the object. Hint: Consider the final center of mass (x,y) relative to the axes shown in the figure. Note the positions of the boxes relative to the axes and to one another. Determine the positions, x and y, of the center of mass for the system below. Enter to 3 significant figures Center of mass (x, y): ( d1 m1 d3 d2 h1 ✔cm = m3 m2 h2 ✔ cm) 11h3 X

A 3 kg plank is 0.6 m in length and has its center of mass at the geometrical center. Masses of 1 kg an 3 kg are attached at opposite ends of the plank. Find the center of mass of the whole system. 1 kg 3 kg Where is the COM? 3 kg