:ö +ÖH a. e. CH CH NHCH, ÖCH, b. CH,NH-CH=CHCH3 f. CH;CH-CH=CHCH3 d.

c) Show Transcribed Text H₂SO4 Give a reasonable mechanism for this rxn, be sure to draw all intermidiates and use arrow pushing. Pay attention to syereochemistry and draw the most stable resonance contributer.

Which of the following below would be considered a good Lewis Acid/Electrophile? A) OCH3 B) BF3 C) SCH3 D) CH3OH E) all of above

All resonance structures with arrow. Major resonance?

1. Consider two SN1 reactions: (A) water and tert-butylbromide and, (B) water and 2- bromopropane, both having the same concentration of reactants. a. Draw the reactants (nucleophile and substrate) for both reactions (A & B). b. Draw a curved arrow mechanism for the reaction between water and tert-butylbromide (A). Show all reactants, intermediates, and products do not show transition state structures. c. Draw products of each reaction (A & B). d. Predict which reaction will be faster (A or B). - e. Draw an energy vs. reaction coordinate diagram showing only the rate-determining step for both reactions on the same set of axes (axes available on the next page). Draw the reaction (A) with a dotted line and (B) with a solid line, and assume that the potential energies of the reactants are the same in both reactions (i.e. the only difference is in the energies of the two different transition states and resulting intermediates).

In the picture, Each of the following compounds has more than one kind of (a-H's). First draw all a-H in, and circle the ones that are more acidic (that is, the ones more likely removed with a suitable base) in each compound. Thank you!

For the reaction given below, draw a mechanism (curved arrows) and then predict which side of the reaction is favoured under equilibrium conditions. Include lone pairs and formal charges. Predict which side of the reaction is favored under equilibrium conditions, and explain your choice.  a. the reactants are favored, because the negative charge on the electronegative oxygen atom is more stable (making it the stronger base). b.  the products are favored, because the negative charge on the electronegative oxygen atom is more stable (making it the weaker base). c. the products are favored, because the negative charge on the large sulfur atom is more stable (making it the weaker base). d. the reactants are favored, because the negative charge on the large sulfur atom is more stable (making it the stronger base).

Draw all resonance structure for each radical compound.

we will discuss whether a methoxy group is electron donating or electron withdrawing. We will see that there is a competition between two factors. The methoxy group might be considered electron-withdrawing because of induction, or it might be considered electron-donating because of resonance. Below are the resonance structures of compound 1. Draw the missing curved arrow(s) to convert the each resonance structure into the next one...

Draw all the resonance contributors for the phenoxide in below. draw only one of the two equivalent "Kekule benzene" structures. include all valence lone pairs in answer.