o ds ci2-i)} + 5 iz +3 d'i. dt step 3:- Simplity v tD= 12 i, - 5i2 5 die dt 5 di, + 5i2 +3 d?iz dt dtz 0= -5D i, + ( 30? +5D+5] iz D= d dt %3D 1

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Continue the solution by giving a step 4: 

72
1/5F
In
3H
The
given circuit
Step!:
lurrent loops
7n
SF
Ve = Ri
L di
at
iこ cdve
dt
write kVL in loop I
7i, +5 (i, -iz)
12 i, - 5iz
Vt) =
vet) =
>
write
KVL in loop 2
0= 5(i2 -i,) +Siz at -
V5
vÉS iz at + 3 die
dt
Step 2:-
Remove Integals
Diffren hute esuiton @
with vespect to t'
o-d$ Cie-i)s + 5 i2 +3 di.
dt
step 3:-
Simplity
VCt)= 12 ů, - 5i2
5 diz
dt
5 di,
+ 5i2 +3 d?iz
dt
dtz
0= -5Di, +( 30?+50] iz
+ 5
D=
Transcribed Image Text:72 1/5F In 3H The given circuit Step!: lurrent loops 7n SF Ve = Ri L di at iこ cdve dt write kVL in loop I 7i, +5 (i, -iz) 12 i, - 5iz Vt) = vet) = > write KVL in loop 2 0= 5(i2 -i,) +Siz at - V5 vÉS iz at + 3 die dt Step 2:- Remove Integals Diffren hute esuiton @ with vespect to t' o-d$ Cie-i)s + 5 i2 +3 di. dt step 3:- Simplity VCt)= 12 ů, - 5i2 5 diz dt 5 di, + 5i2 +3 d?iz dt dtz 0= -5Di, +( 30?+50] iz + 5 D=
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