Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- FBD: The mass of a pendulum is connected to a spring with a spring constant Kas shown in the figure. The spring stays vertical all the time with the help of a massless follower. The vertical distance between the fixed point O and the path of the massless follower is 2L. Use Newton's second law and find the equation of motion of the system in terms of 0. 762 mgbi Img 2L L bil Nig K 777777 P EMO = Jaz ->0₂ ?arrow_forwardConsider a mass-and -spring system containing two masses m1=1 and m2=1 whose displacement functions x(t) and y(t) satisfy the differential equations : x'' = -10x + 2y y'' = 3x -15y Assume that the two masses start in motion with the initial conditions x(0) =32, x'(0)=6, and y(0)=36, y'(0)=3 and are acted on by the same force F1(t)=F2(t)=-1320cos(7t). Describe the resulting motion as a superposition of oscillations at the three different frequencies. The three frequencies consist of lower, higher, and the forcing frequency. For each one please compare the magnitude of m2 to m1.arrow_forward7. Consider the pendulum-and-spring system depicted below. Here the mass of the pendulum rod is negligible. Derive the equation of motion and the natural frequency using the energy method. k m y youarrow_forward
- A 225kN test aircraft moving with velocity v = Xo = 25 km/h collides with a rigid barrier at t = 0. As a result of the behaviour of its energy absorbing capabilities, the response of the aircraft to the collision can be simulated by the damped spring- mass oscillator shown with k = 3MN/m and c = 840 kN. s/m. Assume that the mass is moving to the left with a velocity vo = xo = 25 km/h and the spring is unstretched at t = 0 determine the aircraft's deceleration: a) Immediately after it contacts the barrier; b) att = 0.04s and; c) at t= 0.08s. Vo = ******** xo ****** Vo = xo www m Figure Q5 - Aircraft Collision F(t)arrow_forwardObtain the state model for the two-mass system whose equations of motion are m₁x₁ + k₁(x₁ − x₂) = f(t) m₂x₂ − k₁ (x₁ - x₂)+k₂x₂ = 0arrow_forward4- The logarithmic decrement can be obtained as & In*, is it possible to get a negative value of 8 when the system is damped (3 < 1)? Why?arrow_forward
- The location h of a mass m on the end of a spring with a dampening factor k at time t is described by the following differential equation: m 2²h at² What type of variables are h, m, k, and t? + kh= 0arrow_forwardConsider the two-mass system shown below. The system is free to move in the x₁ - x₂ plane. 1. Obtain the FBD 2. Obtain the EOM 3. Using Modal Analysis, obtain the response of the system x2 X4 3k 4k 4k quing m m=10kg, k = 100 N/m m k 2k m 4karrow_forward8.6 Obtain the total response of the following models. 6x + 5x = 20u,(t), x(0) = 0 b. 6x + 5x = 20u, (t), x(0) = 1 a. C. 13x − 6x = 18u, (t), x(0) = −2 -arrow_forward
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