nystate Auto Insurance Company took a random sample of 360 insurance claims paid out during a 1-year period. The average claim paid was $1590. Assume σ = $256. Find a 0.90 confidence interval for the mean claim payment. (Round your answers to two decimal places.) lower limit     $  upper limit     $  Find a 0.99 confidence interval for the mean claim payment. (Round your answers to two decimal places.) lower limit     $  upper limit     $

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Q: any state Auto Insurance Company took a random sample of 380 insurance claims paid out during a…

A: The summary of statistics is, Critical values: By using the z-tables, the critical value at 10%…

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A: Given information Sample size(n) = 25 Sample mean x̅  = $82426 Population standard deviation = $2000…

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A: Given data,

Q: Anystate Auto Insurance Company took a random sample of 378 insurance claims paid out during a…

A: given data  n = 378 x¯ = 1550σ = 264 find 90% ci for μ.

Q: interval at a 95% confidence level. Give your answers to one decimal place. Interpret your…

A: Given : Sample Size, n = 18 Sample Mean, x̄ = 35 sample standard…

Q: Anystate Auto Insurance Company took a random sample of 364 insurance claims paid out during a…

A: Given that  Sample size n =364 Sample mean =1555 Population standard deviation =264

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A: According to the given information,Population proportion, p = 34% = 0.34Sample size, n = 368Number…

Q: Anystate Auto Insurance Company took a random sample of 196 insurance claims paid out during a…

A: From the provided information, Sample size (n) = 196 Sample mean (x̄) = $1560 Standard deviation (σ)…

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A: Confidence interval is an inference process which is used to estimate the population parameter. The…

Q: Anystate Auto Insurance Company took a random sample of 366 insurance claims paid out during a…

A: Since we know population standard deviation, use z-distribution to find z-critical value. Find…

Q: Find a 0.90 confidence interval for the mean claim payment. (Round your answers to two decimal…

A: Given that X bar = 1565; sigma = 264; n=376 We need to find the 90% confidence interval for the mean…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

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A:

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Using excel formula “=T.INV(1-(0.2/2),22)”, the critical value of 80% confidence level is 1.321.

Q: In a survey, 25 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

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Q: Anystate Auto Insurance Company took a random sample of 362 insurance claims paid out during a…

A:

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Sample mean = x̅ = 46 Sample size = n = 23 Sample S.D = s = 12 Standard Error = s/√n  = 12/√23…

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A: The sample mean is 32 and standard deviation is 14.

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A: It is given that, Sample mean, x-bar = 1525. Population standard deviation, sigma is 234. The sample…

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A: Here we have,   sample size : n = 63sample average bonus: x¯ = $50,000sample standard deviation : s=…

Q: Write your complete solutions and box your answers. Regression methods were used to analyze the data…

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Q: In a survey, 21 people were asked how much they spent on their child's last birthday gift. The…

A: From the provided information, Sample size (n) = 21 Sample mean (x̅) = $46 Sample standard deviation…

Q: In a survey, 20 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=20Mean(x)=50standard deviation(s)=19c=90%

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Q: Anystate Auto Insurance Company took a random sample of 374 insurance claims paid out during a…

A: The provided information are:

Q: Anystate Auto Insurance Company took a random sample of 376 insurance claims paid out during a…

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A: The confidence interval (CI) is a range of values that’s likely to include a population value with a…

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A:

Q: A random sample of 35 customers has an average order size of $80, and a population standard…

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