Solution: Conservation of momentum: mad tmal—oa)=mnon+mu—0H) Solve for VH: Mn VH - -Vn (Eqn. 1) MH Conservation of energy (with positive Wnc): 2 (mav²) + Wnc = ½m v² + ½ mμv² пс Plug in for vд from (Eqn. 1): 2 (mana) +Wnc = = muốn tầm Clean up: mdv² + Wnc = Mn mn + MH -) v²/2 ½/ (m Mn MH Un 2 .)² Plug in masses of "particles" and Wnc: (2.0147kg)v² + (3.96 × 10¹4 J) = (.6733kg)v Nuclear Fusion Reaction In a human-scale model of a nuclear fusion reaction, two "deuterons" smash together head-on. Each has a mass of 2.0147kg and is moving at speed vd. The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate "neutron" (mass 1.0090kg пс ). Amazingly, this reaction produces a positive Wn of 3.96 × 10 14 J -- by converting mass into kinetic energy as predicted by Einstein's E = mc². The "neutron" moves with a speed of un after the reaction. E 4 Vd 1.63×107 m S Type your answer... + D D 3Не N. Proton Neutron http://fusion.srubar.net Un ×107: m S &

What is the approximate uncertainty in the mass of a muon, as determined from its decay lifetime?

In a certain region,                               J = (2yax + xzay + z3az ) sin 104t A/mfind ρv if ρv (x, y, 0, t) = 0.

4. Typical measurements of the mass of a A particle (1230 MeV/c²) are shown in the figure. Although the lifetime of the delta is much too short to measure directly, it can be calculated from the energy- time uncertainty principle. Estimate the lifetime from the full width at half-maximum of the mass measurement distribution shown. 25 MA Le 1000 1100 1200 1300 1400 1500 Mass of the delta particle M/ Number of mass me amare in each bin