nts were grown using 5 different fertilizers and the number of flowers that each plant produced was counted. to test for a significant effecct of fertilizer on the number of flowers at the 5% level of significance. f-ratio and the f critical values were calculated.  type both null and the alternative hypothesis for this test. your hypothesis must include the term plant growth and fertilizers.

Approximately 58% of all people are able to wink with both eyes. Is this percent different for people who wear glasses? A researcher tests 319 people who wear glasses and found that 204 could wink with both eyes. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer z-test for the difference between two population proportions t-test for a population mean z-test for a population proportion t-test for the difference between two dependent population means t-test for the difference between two independent population means  The null and alternative hypotheses would be:  H0:H0:  Select an answer μd p1 p μ1 μ  Select an answer ≥ = ≠ ≤    H1:H1:  Select an answer μ μ1 p p1 μd  Select an answer < ≠ > =   The test statistic ? z t  =  (round to 3 decimal places) The p-value =  (round to 4 decimal places) The p-value is ? > ≤  αα. Based on this, we should Select an answer accept reject fail to reject  the null hypothesis. Explain…

Phosphorous is a chemical that is found in many household cleaning products. Unfortunately, phosphorous also finds its way into surface water, where it can harm fish, plants, and other wildlife. Two methods of phosphorous reduction are being studied. At a random sample of 7 locations, both methods were used and the total phosphorous reduction (mg/L) was recorded. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value a small amount and thereby produce a slightly more "conservative" answer. Site 1 2 3 4 5 6 7 Method I: 0.013 0.020 0.015 0.055 0.007 0.002 0.010 Method II: 0.014 0.045 0.017 0.039 0.017 0.001 0.013 Do these data indicate a difference (either way) in the average reduction of phosphorous between the two methods? Use α = 0.05. (Let d = Method I − Method II.) (i) What is the level of significance?   What is the value of the sample test statistic? (Round…

The old variety of a plant has 70% pink flowers. A new variety is developed. In a random sample of 93 plants from the new variety, 59 had pink flowers. Test the claim that the percent of plants with pink flowers for the new variety is different than 70%. Use a 0.10 level of significance.   Question 6 options:   DO NOT Reject H0 Using a 0.10 level of significance there is not evidence to say the proportion of pink flowers is different than 0.70   Reject H0 Using a 0.10 level of significance there is evidence to say the proportion of pink flowers is not different than 0.70

Las Vegas has seen increased competition from Singapore and Macau for customers in the casino resort industry. One measurement of success is the average length of stay by visitors. The data in this file show the number of days a random sample of visitors stayed at each location. a. Using α = 0.05 to determine if there is a difference in the average length of stay by visitors for the three locations. Follow the steps as outlined in the exercises. b. If warranted, perform a multiple comparison test to determine which pairs are different using α = 0.05. c. Verify your results using Excel.

Help me answer the question. Choices are already given.

A repeated-measures and an independent-measures study both produce a t statistic with df=20. How many subjects participated in each experiment?

A company that has a 10% market share (they sell their product to 10% of all potential buyers) launches a marketing campaign. At the end of the campaign period, the company conducts a survey in order to assess whether its market share has increased. The result of the survey issued to 500 customers was 12.5%.h0= p=0.10, h1= p>0.10test statistic= 1.86P value= 0.0314 a. State your conclusion using ΅ = 0.05.b. What would be the potential Type I and Type II errors in this problem? Explain these possible errors in context.

Please let me know if I calculated relative risk correctly. Thank you for your assistance.

Thirty different video games showing drug use were observed. The duration times of drug use ​(in seconds) were recorded. When using this sample for a t test of the claim that the population mean is greater than 92 ​sec, what does df​ denote, and what is its​ value?   what's the value of df?