Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Step 3 Now, if u = 9x + 2, then = -=- / / ² ( 1² αu ) = 1² / / / / / ou du du, This evaluates as follows. (Enter your answer in terms of u. Remember to use absolute values where appropriate.) 11/11/2 du = dx 1x 9x + 2 + C
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Transcribed Image Text:Step 3 Now, if u = 9x + 2, then = -=- / / ² ( 1² αu ) = 1² / / / / / ou du du, This evaluates as follows. (Enter your answer in terms of u. Remember to use absolute values where appropriate.) 11/11/2 du = dx 1x 9x + 2 + C
Evaluate the indefinite integral. dx 9x + 2 Step 1 We must decide what to choose for u. If u = f(x), then du = f'(x) dx, so it is helpful to look for some expression in dx 1 √x + 2 = 19 x ²2 9x + 9x + for which the derivative is also present, though perhaps missing a constant factor. We see that 9x + 2 is part of this integral, and the derivative of 9x + 2 is 9 Step 2 If we choose u = 9x + 2, then du = 9 dx. If u = 9x + 2 is substituted into T dx 9x + 2 We must also convert dx into an expression involving u. Using du = 9 dx, then we get dx = 1/9 then we have 13 *2²2 - 1/1²/10*x =/dx. 9x + 1/9 du. 249 which is simply a constant.
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Transcribed Image Text:Evaluate the indefinite integral. dx 9x + 2 Step 1 We must decide what to choose for u. If u = f(x), then du = f'(x) dx, so it is helpful to look for some expression in dx 1 √x + 2 = 19 x ²2 9x + 9x + for which the derivative is also present, though perhaps missing a constant factor. We see that 9x + 2 is part of this integral, and the derivative of 9x + 2 is 9 Step 2 If we choose u = 9x + 2, then du = 9 dx. If u = 9x + 2 is substituted into T dx 9x + 2 We must also convert dx into an expression involving u. Using du = 9 dx, then we get dx = 1/9 then we have 13 *2²2 - 1/1²/10*x =/dx. 9x + 1/9 du. 249 which is simply a constant.
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