NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid-vapor mixture at a pressure of 140 kPa. The refrigerant absorbs 200 kJ of heat from the cooled space, which is maintained at -10°C, and leaves as saturated vapor at the same pressure. Problem 07.025.c - Total entropy change of the process

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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## Problem 07.025 - Dependent Multi-Part Problem - Assign All Parts

**Note:** This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.

Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid–vapor mixture at a pressure of 140 kPa. The refrigerant absorbs 200 kJ of heat from the cooled space, which is maintained at –10°C, and leaves as saturated vapor at the same pressure.

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### Problem 07.025.c - Total Entropy Change of the Process

Determine the total entropy change for this process.

The total entropy change for this process is \_\_\_\_ kJ/K.
Transcribed Image Text:## Problem 07.025 - Dependent Multi-Part Problem - Assign All Parts **Note:** This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid–vapor mixture at a pressure of 140 kPa. The refrigerant absorbs 200 kJ of heat from the cooled space, which is maintained at –10°C, and leaves as saturated vapor at the same pressure. --- ### Problem 07.025.c - Total Entropy Change of the Process Determine the total entropy change for this process. The total entropy change for this process is \_\_\_\_ kJ/K.
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