Note: Make sure your calculator is in radian mode for this problem, and that you switch it back after this problem. There are two particles (1 and 2) that are moving around in space. The force that particle 2 exerts on 1 is given by: F₁(t)= F₂e (t/T) 1 + Fy sin(2t/T) 3 Where the parameters have the values: F₂ = 16.8 N, F, = -106 N, T = 100 s. We will consider a time interval that begins at t;=0s and ends at t = 243 s. Impulse from 2 on 1, z Impulse from 2 on 1, y Impulse from 1 on 2 V

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The mass of particle 1 is 11kg and the mass of particle 2 is 15kg. The initial velocity for particle 1 is  (-104m/s)i + (216m/s)j and the initial velocity of particle 2 is (75m/s)i + (-152m/s)j.

**Transcription for Educational Website**

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**Note:** Make sure your calculator is in radian mode for this problem, and that you switch it back after this problem. There are two particles (1 and 2) that are moving around in space. The force that particle 2 exerts on 1 is given by:

\[ \vec{F}_{21}(t) = F_{ze}^{-t/(17\,T)}\, \hat{i} + F_y \sin(2\pi t/T)\, \hat{j} \]

Where the parameters have the values: \( F_z = 16.8\, \text{N} \), \( F_y = -106\, \text{N} \), \( T = 100\, \text{s} \).

We will consider a time interval that begins at \( t_i = 0\, \text{s} \) and ends at \( t_f = 243\, \text{s} \).

---

### Calculations:

- **Impulse from 2 on 1, \( x \)**
- **Impulse from 2 on 1, \( y \)**
- **Impulse from 1 on 2**
- **Average Force from 1 on 2**
- **Average Force from 2 on 1**
- **Final Velocity of Particle 1**
- **Final Velocity of Particle 2**
- **Momentum Change of the System**
- **Change in Kinetic Energy of Particle 1**
- **Change in Kinetic Energy of Particle 2**
- **Change in Kinetic Energy of the System**

---

### \( x \) Displacement of Particle 1

What is the \( x \) displacement for particle 1?  
[Click here for a hint](#)  

\[
\Delta x_1 = 19819.96633\, \text{m}
\]

- **Hint:** 
- **Hint:** 
- **Hint:** 
- **Hint:** 
- **Hint:** 
- **Hint:** 

---

### \( y \) Displacement of Particle 1

--- 

This section contains dynamic calculations related to forces, impulses, and displacements experienced by particles moving in space. Each element is interactive, offering hints to guide understanding and facilitate learning.
Transcribed Image Text:**Transcription for Educational Website** --- **Note:** Make sure your calculator is in radian mode for this problem, and that you switch it back after this problem. There are two particles (1 and 2) that are moving around in space. The force that particle 2 exerts on 1 is given by: \[ \vec{F}_{21}(t) = F_{ze}^{-t/(17\,T)}\, \hat{i} + F_y \sin(2\pi t/T)\, \hat{j} \] Where the parameters have the values: \( F_z = 16.8\, \text{N} \), \( F_y = -106\, \text{N} \), \( T = 100\, \text{s} \). We will consider a time interval that begins at \( t_i = 0\, \text{s} \) and ends at \( t_f = 243\, \text{s} \). --- ### Calculations: - **Impulse from 2 on 1, \( x \)** - **Impulse from 2 on 1, \( y \)** - **Impulse from 1 on 2** - **Average Force from 1 on 2** - **Average Force from 2 on 1** - **Final Velocity of Particle 1** - **Final Velocity of Particle 2** - **Momentum Change of the System** - **Change in Kinetic Energy of Particle 1** - **Change in Kinetic Energy of Particle 2** - **Change in Kinetic Energy of the System** --- ### \( x \) Displacement of Particle 1 What is the \( x \) displacement for particle 1? [Click here for a hint](#) \[ \Delta x_1 = 19819.96633\, \text{m} \] - **Hint:** - **Hint:** - **Hint:** - **Hint:** - **Hint:** - **Hint:** --- ### \( y \) Displacement of Particle 1 --- This section contains dynamic calculations related to forces, impulses, and displacements experienced by particles moving in space. Each element is interactive, offering hints to guide understanding and facilitate learning.
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