(Note: @ does not include beam weight) @D = 2 kip/ft @= 4 kip/ft 12 ft P₁ = 10 kips (A) f = 5,000 psi; fy = 60,000 psi Unit weight of concrete = 150 lb/cu.ft. 2 in. 28 in. 3 # 11 bars 12 in. 30 in. a) Determine the required shear reinforcement at the most critical section b) Find the location on the beam at which shear reinforcement is not needed

Calculate the uniform load w (in addition to the beam weight) that will cause the section shown to begin to crack if used as a 28-ft simply supported beam. Use normal weight concrete with L=4000 psi. f = 60,000 psi, E₁=29,000 ksi, and the reinforced concrete weight = 150 lb/ft³. 4 in. 28 ft 4 in. 22 in. 30 in. 2 in. 2 in. 3 #9 ● ||—12 in—-|

1.22 Calculate the design moment strength of the precast concrete section shown in Fig. 3.39 using = 4 ksi and f,= 60ksi. 589 20 19"

Given the concrete (f c=6000 psi) I-beam shown in Figure 1 for the given loading: -draw the shear & moment diagrams -determine Vmax & Mmax -using ASD (Allowable Stress Design) method, check to see if the given loading produces stresses within the given allowable range (check both Omax & Vmax) Using ACI 318-99, allowable stresses are -for flexure, f = .45f'c -for shear, v. = 1.1√f. (HINTS: 8² -note that the beam is symmetric about both axes -Ix for a triangle is (1/36)bh³+Ad² ) 30 kips 16' 10 kip/ft 22' 20 kips 3'-4' -1-6 -1'-6" Figure 1 1'-

PLEASE SOLVE AND BOX ALL FINAL A LITTLE CONFUSED