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Normalize (z) = 3f2(x) +2f3(x). You can think of functions being 0 beyond the [0, L] interval, where L = 3, 2, 5.

Normalize (z) = 3f2(x) +2f3(x). You can think of functions being 0 beyond the [0, L] interval, where L = 3, 2, 5.

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter2: Functions
Section2.4: Average Rate Of Change Of A Function
Problem 2E
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Normalize (r) = 3f₂(x) + 2f3(x). : You can think of functions being 0 beyond the [0, L] interval, where L = 3, 2, 5.
Transcribed Image Text:Normalize (r) = 3f₂(x) + 2f3(x). : You can think of functions being 0 beyond the [0, L] interval, where L = 3, 2, 5.
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