Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- 1. The tensile strength vs. temperature curves of aluminum are plotted below. Explain the meaning of these two curves. 400 Ultimate strength 300 Yield strength 200 100 -200 -150 -100 -50 50 100 150 200 250 Temperature, °C Strength, kPaarrow_forwardA polymer cylinder (2) is clamped between rigid heads by two steel bolts (1). The steel [E = 29,000 ksi; a = 6.5×10-6/°F] bolts have a diameter of 0.50 in. The polymer [E = 380 ksi; a = 39.7x 10-6/°F] cylinder has an outside diameter of 7.0 in. and a wall thickness of 0.40 in. Assume a = 22 in. and b = 30 in. If the %3D temperature of this assembly changes by AT = 125°F, determine: (a) the normal stress in the polymer cylinder. (b) the normal strain in the polymer cylinder. (c) the normal strain in the steel bolts. |(1) (2) C а (1) b. Answer:arrow_forwardThe assembly shown in the figure consists of an aluminum tube AB and a steel rod BC. The rod is attached to the tube through the rigid collar at B and passes through the tube. The cross-sectional area of the rod is 75 mm2 and the cross-sectional area of the tube is 400 + UV in mm2, where UV is 99. A tensile load of 80 kN is applied to the rod. Take Est = 200 GPa for the steel rod, Eal = 70 GPa for the aluminum tube. Determine: (a) the displacement of end C with respect to end B (i.e., the elongation of the steel rod), (b) the displacement of end B with respect to the fixed end A (i.e., the shrink of the aluminum tube), (c) the displacement of the end C of the rod (i.e., (a) + (b)).arrow_forward
- #2 will upvote to anyone who will answerarrow_forwardA rigid bar, AB, is pinned at point B. Two other bars, AC and AD, are connected to point A to provide support for AB. We are investigating the behavior of this system under a specific load. Key Details: Bar properties: Material: Steel with Young's modulus (Esteel) of 200 GPa and coefficient of thermal expansion (a) of 11.7 x 10^-6 /°C. Cross-sectional area: AC: 1960 mm² AD: 1250 mm² Length: AC: √2 meters (square root of 2 meters) AD: 1 meter Inclination angles: AC: θ₁ (theta 1) = 30° from horizontal AD: θ₂ (theta 2) = 20° from horizontal Load on bar AB: Idealized linearly increasing load with a maximum value of 30 kN/m at point B. Problem Objectives: Determine the internal forces (axial forces) acting within bars AC and AD due to the applied load on AB. Calculate the displacement of point A in both horizontal (dA,x) and vertical (dA,y) directions.If the bar is cooled by 10°C, what would be the: Determine the internal forces (axial forces) acting within bars AC and AD…arrow_forwardAt a temperature of 37.4 °C a 0.49-mm gap exists between the ends of the rods shown. At a later time when the temperature has reached 128.7°C, determine the change in length of the steel rod if L = 328.25 mm and M = 215 mm. Round off the final answer to four decimal places.arrow_forward
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