ney: Load (L) = 5 kgs E = Effort F = Fulcrum Weight of forearm = 1.8 kgs L- Load Biceps brachi muscle Distance of load from elbow joint = 35 cm Effort (E) = contraction of biceps brachi Distance of center of mass of forearm from elbow = 17 cm Distance of tendon from elbow = 4 cm A) Draw the free-body diagram to represent the forces and moments Load (L) = weight of objed plus forearm B) Write the torque equation for static equilibrium Fulcrum (F) = elbow joint

Analyze the Barbell press (overhead or military press) exercise by breaking the exercise into a lifting phase and lowering phase. For each phase, match the joint movements occurring and then match the force causing movement (muscle or gravity), the force resisting movement (muscle or gravity) and the functional muscle group, type of contraction with each joint for the respective phase. Lifting phase - Elbow - Movement occurring Lifting phase - Elbow - Force causing movement Lifting phase - Elbow - Force resisting movement Lifting phase - Elbow - Functional muscle group, type of contraction Lifting phase - Glenohumeral - Movement occurring Lifting phase - Glenohumeral - Force causing movement Lifting phase - Glenohumeral - Force resisting movement Lifting phase - Glenohumeral - Functional muscle group, type of contraction Lifting phase - Shoulder girdle - Movement occurring Lifting phase - Shoulder girdle - Force causing movement Lifting phase -…

2. a) Label the system provided below, including the reference frame, moment arms and vector forces with the information provided. Internal moment arm = 4cm +0.04m External moment arm relative to the segment weight = 25cm 0.25m External moment arm relative to the load weight = 45cm 40.45m Segment weight = 50 N Load weight = 100 N Lower leg segment angle relative to horizontal plane = 45° Quadriceps tendon angle = 45° Axis of rotation MF SW LW 2b) Using the figure in 2a., calculate the external torque of the system relative to the normal component of segment and load weights listed above. 2c) Calculate the amount of both the tangential component of the muscle force and the muscle force itself required to keep this system in a state of static equilibrium.

With the shoulder flexed at 30°, the moment arm of the deltoid muscle is 2.0 cm. Solve for the force exerted by the deltoid muscle at the glenohumeral joint give the following assumptions: The deltoid is the only active muscle at the glenohumeral joint The weight of the humerus is 48 N. The center of gravity of the humerus is located 30 cm from the shoulder center of rotation STATIC EQUILIBRIUM EQUATIONS CONSIDERING ONLY THE DELTOID MUSCLE Fo MA = 18 Cn COR B=55". 0-30° RaF 30 cm FG = 24 N