Neutrons (mass 1) are being scattered by a nucleus of mass A(A > 1). In the center of the mass system the scattering is isotropic. Then, in the lab system the average of the cosine of the angle of deflection of the neutron is A cos 0 +1 Jo (A² +2ACOS e + 1)/² 1 (cos v) = sine do. Show, by expansion of the denominator, that (cos v) = 2/3A.
Neutrons (mass 1) are being scattered by a nucleus of mass A(A > 1). In the center of the mass system the scattering is isotropic. Then, in the lab system the average of the cosine of the angle of deflection of the neutron is A cos 0 +1 Jo (A² +2ACOS e + 1)/² 1 (cos v) = sine do. Show, by expansion of the denominator, that (cos v) = 2/3A.
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![Neutrons (mass 1) are being scattered by a nucleus of mass A(A > 1).
In the center of the mass system the scattering is isotropic. Then, in
the lab system the average of the cosine of the angle of deflection of
the neutron is
A cos0 +1
(cos ) = 5 (A² + 2Acos 0 + 1)/2
1
sine do.
Show, by expansion of the denominator, that (cos v) = 2/3A.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96f9d221-af37-4dea-a548-96bef2569cdc%2Ffcdff57f-c01b-4713-9811-143f6d844e56%2F1bmofs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Neutrons (mass 1) are being scattered by a nucleus of mass A(A > 1).
In the center of the mass system the scattering is isotropic. Then, in
the lab system the average of the cosine of the angle of deflection of
the neutron is
A cos0 +1
(cos ) = 5 (A² + 2Acos 0 + 1)/2
1
sine do.
Show, by expansion of the denominator, that (cos v) = 2/3A.
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