Network address: 220.100.100.0 Number of needed hosts: 45 Default subnet mask: New subnet mask: Number of subnets created: Number of hosts per subnet: First usable address of the first subnet: Last usable address of the first subnet: Broadcast address of the first subnet: First usable address of the last subnet: Last usable address of the last subnet: Broadcast address of the last subnet:

Network address: 220.100.100.0 Number of needed hosts: 45 Default subnet mask: New subnet mask: Number of subnets created: Number of hosts per subnet: First usable address of the first subnet: Last usable address of the first subnet: Broadcast address of the first subnet: First usable address of the last subnet: Last usable address of the last subnet: Broadcast address of the last subnet:

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter13: Internet And Distributed Application Services

Section: Chapter Questions

Problem 15VE

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NAT translation table LAN side addr WAN side addr 135.122.200.215 10.0.1.15 10,0.1.13 address 135.122.200.215 S: 10,0,1.27 2 D: 1 D: S: S: D: S: 10,0.1.15 D: 135.122,200,215 10.०.1.22
Subnetting Complete the given tables below: # of Subnets # of hosts per subnet Network Address of the first subnet Network Address of the last subnet Subnet Mask 1. 101.138.121.114 /22 --> /25 2. 221.17.27.41 /24 ---> /26 3. 65.120.65.162 /18 ---> 20 #hosts Subnet Mask in Binary Subnet Mask in Decimal Prefix 35 1289 130
Complete the given tables below: # of Subnets # of hosts per subnet Network Address of the first subnet Network Address of the last subnet Subnet Mask 1. 101.138.121.114 /22 --> /25 2. 221.17.27.41 /24 ---> /26 3. 65.120.65.162 /18 ---> 20 #hosts Subnet Mask in Binary Subnet Mask in Decimal Prefix 35 1289 130
• IPV6 addresses use 128 bits to represent an address which includes bits to be used for subnetting. The second half of the address (least significant 64 bits) is always used for hosts only. Therefore, there is no compromise if we subnet the network. Use the Figure below to Create five subnets using route prefix 2001:db:acad::/48 (1 Marks) Routing Prefix Subnet ID Interface ID 48 Bits 16 Bits 64 Bits
Refer the exhibit and the required number of hosts given. Subnet the address 192.168.50.0/24 for the required number of hosts using VLSM and complete the subnet table using the following instructions: NW: 192.168.50.0/24 NET-X: 45 USABLE HOSTS NET-Z: 2 USABLE HOSTS NET-Y: 25 USABLE HOSTS ------ GO/O R2 G0/0 GO/1 GO/1 R1 PC2 PC1 Assign the first subnet to network with the highest host requirement. Assign the second subnet to the network with the second highest host requirement. Assign the third subnet to the network with the third highest host requirement. Subnet Table: Subnet No. of Subnet First Last Usable Broadcast Subnet Name Usable Address Usable Host Address Mask hosts Host Address required Address
2. Subnetting a subnet or using variable-length subnet mask (VLSM) was designed to maximize addressing efficiency. You are required to subnet, based on the number of hosts, including router interface and WAN interface and WAN connections for the following scenario: •Toronto: 60 host addresses •Montreal: 28 host addresses •Ottawa: 12 host addresses •Vancouver: 12 host addresses •WAN1: 2 host addresses •WAN2: 2 host addresses •WAN3: 2 host addresses Using the given address block of 192.168.15.0/24, you can design an address scheme for the network to meet its requirements and save potential addresses. The data for Toronto is given to help you to fill the remaining all other columns. Name Toronto Montreal Ottawa Vancouver WAN1 WAN2 WAN3 Required no of addresses 60 28 12 12 ~~ 2 2 2 Subnet Address 192.168.15.0 Address Range .1 - .62 Broadcast Address .63 Network/ Prefix 192.168.15.0 /26 19
Consider a local network with a 1 Gbps access link to the Internet. Hosts on this network are accessing resources with an average size of 2 MB from a distant server at an average rate of 50 requests per second. a. What is the link utilization of the access link to the internet? b. Suppose these requests were to go through a caching proxy server. What would the link utilization to the internet be if half of all requests were served from the cache of the proxy server? с. resources never being needed for example.) Would this still provide any advantages to the end user? Would there be any disadvantages to the end user? Suppose the proxy server could not serve any content from cache (due to the same
An IP address can be written as a 32-bit number. For a class B network, the two most significant bits are set to 10. The 16 most signi cant bits are used as a network ID, and the 16 least signi cant bits are used as a host ID. However, the host ID cannot be all 0's or all 1's. How many hosts (i.e., host IDs) can there be on a class B network?
SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 : A 175 hosts QUESTION 2 OF 10 Answer How many hosts can there be in this address space? 144.145.110.0/23 B Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. 84 hosts
R6Fragmentation of an IP datagram takes place if its size is larger than the MTU of the subnet over which the datagram will be routed. Most IP datagram reassembly algorithms have a timer to avoid having a lost fragment tie up reassembly buffers forever. Suppose a datagram is fragmented into four fragments. The first three fragments arrive, but the last one is delayed. Eventually the timer goes off and the three fragments in the receiver's memory are discarded. A little later, the last fragment stumbles in. What should be done with it?
1) A /24 address has two subnets. What is the subnet mask in dotted notation. 2) A /24 address has four subnets. What is the subnet mask in dotted notation. 3) A /20 address has 4 subnets. What is the subnet mask in dotted notation.
SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 175 hosts QUESTION 3 OF 10 A Answer What is the subnet address of subnet A? (CIDR notation) 144,145.110.0/23 Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. B 84 hosts