Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 0 -4000 -5000 O 11.7 O None of these. O 6.0 8.0 0 O 12.0 5.0 -3,000 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.25/cu. yd. ● Borrow Cost: $4.50/cu. yd. Overhaul Cost: $0.75/sta*cu. yd. Free Haul Limit: 600 ft. Compute the limit of economic haul: 1,500 2,100 0 5 6.0 8.0 10 3,500 + 7.1 2,100 -1,100- Stations 15 7.0 H 8.0 6.0 0 20 1,500 750 25

Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 0 -4000 -5000 O 11.7 O None of these. O 6.0 8.0 0 O 12.0 5.0 -3,000 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.25/cu. yd. ● Borrow Cost: $4.50/cu. yd. Overhaul Cost: $0.75/sta*cu. yd. Free Haul Limit: 600 ft. Compute the limit of economic haul: 1,500 2,100 0 5 6.0 8.0 10 3,500 + 7.1 2,100 -1,100- Stations 15 7.0 H 8.0 6.0 0 20 1,500 750 25

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

Net Cumulative Yardage ● 5000 4000 3000 2000 C 1000 -1000 -2000 -3000 -4000 -5000 O 8.0 Compute the limit of economic haul: O None of these. 9.2 5.0 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.00/cu. yd. Borrow Cost: $3.25/cu. yd. Overhaul Cost: $1.25/sta*cu. yd. Free Haul Limit: 600 ft. 6.0 -3,000 9.4 1,500 10 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 $10,590.00 Compute the total overhaul cost: O None of these. Given the Mass Haul Diagram above and the following information: Excavation Cost: $3.50/cu. yd. Borrow Cost: $3.75/cu.yd. Overhaul Cost: $1.50/sta*cu. yd. ● Free Haul Limit: 600 ft. O $1,590.00 5.0 O $600.00 -3,000 O $990.00 1,500 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
Net Cumulative Yardage ● 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 0 O $34,000.00 Compute the total excavation cost: $10,000.00 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.00/cu. yd. Borrow Cost: $4.25/cu. yd. Overhaul Cost: $1.25/sta*cu. yd. Free Haul Limit: 600 ft. $32,000.00 5.0 None of these. -3,000 O $26,000.00 1,500 5 2,100 Mass Diagram 6.0 8.0 10 3,500 7.1 2,100 -1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2.100 7.0 2000 8.0 1,500 1,500 8.0 ------ 1000 -1,100 - 7.1 6.0 750 5.0 0. -1000 3-2000 -3000 -3,000 -4000 -5000 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total cost in borrow to the nearest dollar? O $0 O $2,625 $2,813 $5,625 O Non Net Cumulative Yardage
Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2,100 7.0 2000 8.0 1,500 1,500 8.0 ----- 1000 1,100 7.1 6.0 750 5.0 0. -1000 -2000 -3000 -3,000 -4000 -5000 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total quantity of waste in cubic yards? O 2100 O 1500 400 O 750 O None of the above Net Cumulative Yardage
The following net accumulations were calculated. The free haul area begins at station 4+30 and continues to 14+30. If the overhaul is charged at $10/yd³ station, what is the total overhaul cost ($)? Round to the nearest cent. from station to station net accumulation, yd³ 2+60 3+00 3.85 3+00 4+00 5.85 4+00 4+30 8.35 Response Feedback: 10x8.35x0.9281
If the free haul area is between 4+30 and 14+30, what is the average haul distance (ft) for the net volume of material taken from the section between station 2+60 and 3+00? Response Feedback: The average distance between 2+60 and 3+00 is 20 ft. Add that to the distance from 3+00 to the free haul area, which begins at 4+30.
For the following mass haul diagram loop shown below, calculate the cost of earthwork, including excavation and hauling given that the cost of excavation is $2.0/m³ and the cost of overhaul is $0.150/m³.station. (Hint: Numbers shown on the loop are accumulative volumes (m³)) 1760 2150 2280 FHD = 200 m LEHD = 350 m
If the free haul area is between 4+30 and 14+30, what is the average haul distance (ft) for the net volume of material taken from the section between station 2+60 and 3+00? 32
Q1) For the following portion of mass haul diagram (each station is 50 m) answer the following questions: Station 4+00 7+00 6+00 5+00 3+00 2+00 1+00 0+00 -100 200 300 400 500 600 -700 -800 A) If the free haul distance =150 m, find the total cost within the free haul distance if the cost of excavation and transporting up to 150 m = 0.5 JD/ m? B) Find the limit of economical haul distance if the cost transporting is 0.1 JD/ m' for each 30 m beyond the first 150 m? C) Find the volume of waste and borrow materials? D) On the figure above specify the following: · Free haul distance and volume • Limit of economical haul distance and the overhaul volume • The waste and borrow material portion comulative volume m'
↑ NET CUMULATIVE YOS. 5,000 2,000 5 K-X1,000-31, 200 -(-)spoo MASS DIAGRAM 10 7.0 7.3 (-)2,500 1. What is the limit of economic haul in stations? 3. What is the overhaul cost in dollars? STATIONS 2. What is the total cost in dollars for excavation? 4. What is the total borrow cost in dollars? 5. What is the total waste in cubic yards? Limit of Free Haul Cost of Excavation Cost of Borrow Overhaul Price 15 ន 8.0 = 700 ft = $3.50 per cu.yd. = $3.00 per cu. yd. = $1.00 per sta yd. 25 -(-) 8000 (-11,000 (-)2,000 LENGTH IN STATIONS
2. Determine the total cost of earthworks and draw the mass haul diagram of a highway section having the cumulative volume shown in the table below: Station No. ㅇ 5 9 13 15 Cumulative |Volume Given that cost of overhaul = Php 750.00/m²station, cost of borrow = Php 2500.00/m², cost of freehaul = Php 1250.00/m’, and the free haul distance = 9 stations. ㅇ 250 350 220 0 %3D %3D %3D %3D