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please i just need Clear answer with screen shot for output if needed
#include <stdio.h>
#include <omp.h>
int main(int argc, char *argv[]) {
int i, thread_id;
int glob_nloops, priv_nloops; glob_nloops = 0;
// parallelize this chunk of code
#pragma omp parallel private(priv_nloops, thread_id)
{
priv_nloops = 0;
thread_id = omp_get_thread_num(); // parallelize this for loop #pragma omp for
for (i=0; i<100000; ++i)
{
++priv_nloops;
}
// make this a "critical" code section
#pragma omp critical
{
printf("Thread %d is adding its iterations (%d) to sum (%d), ",
thread_id, priv_nloops, glob_nloops);
glob_nloops += priv_nloops;
printf(" total nloops is now %d.\n", glob_nloops);
}
}
printf("Total # loop iterations is %d\n",
glob_nloops); return 0;
}
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- Thread pool is a term that you should be familiar with.Java: In this scenario, one thread is waiting for another thread to finish transfer and vice versa. They are stuck with each other, and the program cannot continue. Thus, deadlock occurs. To avoid deadlock it is necessary to lock accounts in the same order. To fix the program we’ll give each account a unique number so that we can lock accounts in the same order when transferring the money. // // DeadlockAccounts.java // public class DeadlockAccounts { public static void main(String[] args) throws InterruptedException { class Account { int balance = 100; public Account(int balance) { this.balance = balance; } public synchronized void deposit(int amount) { balance += amount; } public synchronized boolean withdraw(int amount) { if (balance >= amount) { balance -= amount; return true; } return false; } public synchronized boolean transfer(Account destination, int amount) { if (balance >= amount) { balance -= amount; synchronized(destination) {…Multi-threading A) Write a Thread class (called worker) that takes two numbers (A and B, A < B) and calculates the products of all numbers between A and B. the result is stored in a local variable than can be accessed through a get method. ). The main thread reads n from the user, then creates two instances of Worker. Each one is requested to calculate the half of numbers between 1 and n. Once they finish, the main thread will gather their results and print the final result (result1 x result2). Example when n=10
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