Need some help with this c++ recursive function: Write the function int countEights(int n). Inside the function, compute recursively (no loops) the count of the occurrences of 8 as a digit inside the parameter n. Except that an 8 with another 8 immediately to its left counts double, so 8818 yields 4. Note that mod (%) by 10 yields the rightmost digit (126 % 10 is 6), while divide (/) by 10 removes the rightmost digit (126 / 10 is 12). Here are some examples: countEights(8) returns 1 countEights(818 returns 2 countEights(8818) returns 4

is it correct ? Write a recursive function that returns the nth number in a fibonacci sequence when n is passed to function. The fibonacci sequence is like 0,1,1,2,3,5,8,13...... Answer: #include <iostream>   using namespace std;   int getFibonacci(int n) {         if (n == 0 || n == 1)         return n;         else         return getFibonacci(n - 1) + getFibonacci(n - 2); }   int main() {     int n = 7;     int result = getFibonacci(n);     cout << result; }

Write code to complete raise_to_power(). Note: This example is for practicing recursion; a non-recursive function, or using the built-in function math.pow(), would be more common.Sample output with inputs: 4 24^2 = 16   def raise_to_power(base_val, exponent_val):   if exponent_val == 0:      result_val = 1   else:      result_val = base_val * ''' Your solution goes here '''    return result_val user_base = int(input())user_exponent = int(input()) print('{}^{} = {}'.format(user_base, user_exponent,      raise_to_power(user_base, user_exponent)))

java netbeans ______ What is wrong with the following code? And correct the error.   int[] array1= {10,20,30}; int result = 0;   for(int i=0 ;i<= array1.length;i++)    result *= array1[i];

Need some help with this c++ problem In order to compute a power of two, you can take the next-lower power and double it. For example, if you want to compute 211 and you know that 210 = 1024, then 211 = 2 × 1024 = 2048. Based on this observation, write a recursive function int pow2(int n) where n is the exponent. If the exponent is negative, return -1. int pow2(int n) {        ..... }

in c++

Using recursion, write a function sum that takes a single argument n and computes the sum of all integers between 0 and n inclusive. Do not write this function using a while or for loop. Assume n is non-negative. def sum(n): """Using recursion, computes the sum of all integers between 1 and n, inclusive. Assume n is positive. >>> sum(1) 1 >>> sum(5) # 1 + 2 + 3+ 4+ 5 15 "*** YOUR CODE HERE ***"

Please solve this in C programming language as early as possible. .Write a recursive function that can use to add all the numbers from 5 to n, where n>5. n will be given by the user. Prototype: int add_num(int n);

in c++ with pre and post pseudocode please dont show me the same code from others please thank u Write the simplest program that will demonstrate iteration vs recursion using the following guidelines -  Write two primary helper functions - one iterative (IsArrayPrimeIter) and one recursive (IsArrayPrimeRecur) - each of which Takes an array of integers and its size as input params and returns a bool such that 'true' ==> all elements of the array are prime, so the array is prime, 'false' ==> at least one element in array is not prime, so array is not prime.  Print out a message "Entering <function_name>" as the first executed statement of each function. Perform the code to test whether every element of the array is a Prime number. Print out a message "Leaving <function_name>" as the last executed statement before returning from the function. Remember - there will be nested loops for the iterative function and there can be no loops at all in the recursive function.…

Python: How do I create a recursive function asterisk with both recursive and base cases?   so for n=3, you would have below; *** ** *   code that I have:   for i in range(n): print("*",end="")