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Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Question
Need help on the last three (The ones with x's) (D) and (E)

Transcribed Image Text:The following table shows the average life expectancy, in years, of a child
born in the given year.t
Year
Life expectancy
2005
77.6
2007
78.1
2009
78.5
2011
78.7
2013
78.8
(a) Find the equation of the regression line. (Let E be the life
expectancy in years andt the number of years since 2005. Round
regression line parameters to two decimal places.)
E(t) =.15t + 77.74
(b) Plot the data points and the regression line.
E
E
79
79
78
78
77
2
4
6
8
2
4.
6
8
E
E
79
79
78
78
77
77
2
4
6
8
2
4
6
8
(c) Explain in practical terms the meaning of the slope of the regression
line. (Round your answer to two decimal places.)
For each increase of 1 in the year of birth the life expectancy
increases by 15
v year.
(d) Based on the trend of the regression line, what do you predict as
the life expectancy of a child born in 2019? (Round your answer to one
decimal place.)
79.4 x yr
(e) Based on the trend of the regression line, what do you predict as the
life expectancy of a child born in 1580? (Round your answer to one
decimal place.)
34.5 x yr
What do you predict as the life expectancy of a child born in 2300?
(Round your answer to one decimal places.)
107.5 x yr
Expert Solution
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Step 1
For part d:
The objective is to predict the life expectancy of a child born in 2019.
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Step 2
According to the part a the equation for linear regression line is given by the formula:
E(t)=.15t+77.74; where year 2005 is taken as the initial year, i.e. t=0 when year is 2005.
Now to predict the life expectancy of a child born in 2019 first find the t since 2005, as
t=2019-2005=14
Now the life expectancy of a child born in 2019 can be calculated by finding E(t) when t=14, as
E(14)=.15(14)+77.74=2.1+77.74=79.84
Thus, life expectancy of a child born in 2019 is approx. 79.8 years.
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Step 3
For part e:
The objective is to predict the life expectancy of a child born in 1580.
Step by stepSolved in 5 steps
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