Need help asap. can you correct all the calculations like the integration part, can you make it a detailed integration solution? Thank you so much, such a big help. Answer from the book: 56 mins 24 sec

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Need help asap. can you correct all the calculations like the integration part, can you make it a detailed integration solution? Thank you so much, such a big help. Answer from the book: 56 mins 24 secs.
12.A swimming pool with plan and section shown in Fig. G is filled with
water. It has two short tubes both with diameter 20cm and C= 0.80
located at the lowest point. Find the time needed to empty the pool
through these tubes.
Given: d₁ =
20cm or 0.20m
d₂= 20cm or 0.20m
C = 0.80
Find:
T =?
15m
4k
1.20 m
Plan
30m
Section
3m
2 tubes
Transcribed Image Text:12.A swimming pool with plan and section shown in Fig. G is filled with water. It has two short tubes both with diameter 20cm and C= 0.80 located at the lowest point. Find the time needed to empty the pool through these tubes. Given: d₁ = 20cm or 0.20m d₂= 20cm or 0.20m C = 0.80 Find: T =? 15m 4k 1.20 m Plan 30m Section 3m 2 tubes
Solution: for rectangular part
450dh
t₁ =
h1 Adh
h2 2CA√2gh
1.8200
1.8 2(0.8) (π) (0.1)^2√19.62h
-1/2
t₁ = 2021.125 ₁²h¹/2dh = 1578.135 s
for triangular part
30
30
x
→X=
-h
h
1.8
1.8
.30
15 (h)dh
t₂:
(0.8)(π)(0.1)^2√19.62h
-1/2 dh
t₂ = 1807.749 s
T = t₁ + t₂
= 1578.135 s + 1807.749 s
= 3385.88 s
dh
=
-1.8
= 1122.847 1³8
1.5m horizontal s
Transcribed Image Text:Solution: for rectangular part 450dh t₁ = h1 Adh h2 2CA√2gh 1.8200 1.8 2(0.8) (π) (0.1)^2√19.62h -1/2 t₁ = 2021.125 ₁²h¹/2dh = 1578.135 s for triangular part 30 30 x →X= -h h 1.8 1.8 .30 15 (h)dh t₂: (0.8)(π)(0.1)^2√19.62h -1/2 dh t₂ = 1807.749 s T = t₁ + t₂ = 1578.135 s + 1807.749 s = 3385.88 s dh = -1.8 = 1122.847 1³8 1.5m horizontal s
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