Structural Analysis
Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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Need asap. Why does h2 is zero?
13. In Fig. H is shown a tank 1.5 by 1.5m horizontal section and 3m high with
two orifices (C=0.60) both 10cm in diameter and 60cm apart. (a) How
much water must be supplied to the tank to keep it always full? (b) If this
supply is cut off, how long
Given: AT= 2.25m; h+ = 3m
1.5 m by 1.5 m
Do1 = 10 cm or 0.10m
W.S (t = 0)
Do2 = 10 cm or 0.10m
C = 0.60
Find: Q₁ =?
t =?
1.20 m
0.60 m
orifice (1)
crifice (2)
100
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Transcribed Image Text:13. In Fig. H is shown a tank 1.5 by 1.5m horizontal section and 3m high with two orifices (C=0.60) both 10cm in diameter and 60cm apart. (a) How much water must be supplied to the tank to keep it always full? (b) If this supply is cut off, how long Given: AT= 2.25m; h+ = 3m 1.5 m by 1.5 m Do1 = 10 cm or 0.10m W.S (t = 0) Do2 = 10 cm or 0.10m C = 0.60 Find: Q₁ =? t =? 1.20 m 0.60 m orifice (1) crifice (2) 100
Solution:
a.) Q = CA,√2gh
Q₁ = (0.6) (π) (0.005)2/19.62(1.2)
= 0.0229 m3/s
Q2 = (0.6) (π) (0.05)2/19.62(1.8)
Q2 = 0.028 m3/s
QT = Q₁ + Q₂ = 0.0229 + 0.028
QT = 0.051 m3/s
ch1
Adh
b.)t₁ = 2₂²
h2 CA√/2gh-Q
-1.2
2.25 dh
=
(2)(0.6) (π)(0.05)^2√19.6h-0.051
900
= 118.0817-
17
t₁= 65.1405 s
1.8
2.25dh
t₂ =
(2)(0.6) (π)(0.05)^2√19.6h-0.051
900
= 61.1236-
17
t₂ = 8.1824 s
T = t₁ + t₂
T = 65.1405 +8.1824
T = 73.32 s
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Transcribed Image Text:Solution: a.) Q = CA,√2gh Q₁ = (0.6) (π) (0.005)2/19.62(1.2) = 0.0229 m3/s Q2 = (0.6) (π) (0.05)2/19.62(1.8) Q2 = 0.028 m3/s QT = Q₁ + Q₂ = 0.0229 + 0.028 QT = 0.051 m3/s ch1 Adh b.)t₁ = 2₂² h2 CA√/2gh-Q -1.2 2.25 dh = (2)(0.6) (π)(0.05)^2√19.6h-0.051 900 = 118.0817- 17 t₁= 65.1405 s 1.8 2.25dh t₂ = (2)(0.6) (π)(0.05)^2√19.6h-0.051 900 = 61.1236- 17 t₂ = 8.1824 s T = t₁ + t₂ T = 65.1405 +8.1824 T = 73.32 s
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