Nationally, patients who go to the emergency room wait an average of 7 hours to be admitted into the hospital. Do patients at rural hospitals have a lower waiting time? The 13 randomly selected patients who went to the emergency room at rural hospitals waited an average of 6.8 hours to be admitted into the hospital. The standard deviation for these 13 patients was 1 hours. What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?vSelect an answerv H1: Select an answer C. The test statistic (please show your answer to 3 decimal places.)

Nationally, patients who go to the emergency room wait an average of 7 hours to be admitted into the hospital. Do patients at rural hospitals have a lower waiting time? The 13 randomly selected patients who went to the emergency room at rural hospitals waited an average of 6.8 hours to be admitted into the hospital. The standard deviation for these 13 patients was 1 hours. What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?vSelect an answerv H1: Select an answer C. The test statistic (please show your answer to 3 decimal places.)

Name: Nationally, patients who go to the emergency room wait an average of
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Description: Nationally, patients who go to the emergency room wait an average of 7 hours to be admitted into thehospital. Do patients at rural hospitals have a lower waiting time? The 13 randomly selected patients whowent to the emergency room at rural hospital

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a 1% level of significance. Give answer to at least 4 decimal places. Hours 45 40 54 54 45 68 48 58 49 50 50 55 What are the correct hypotheses? Ho: Select an answer v hours H: Select an answer v hours Based on the hypotheses, find the following: Test Statistic= p-value= The correct decision is to Select an answer v that the mean number The correct summary would be: Select an answer of hours of all employees at start-up companies work more than the US mean of 47 hours.
The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a 1% level of significance. Give answer to at least 4 decimal places. Hours 45 49 51 55 47 68 46 55 45 49 53 51 47 hours a. What are the correct hypotheses? Ho H Hyp 47 Based on the hypotheses, find the following: b. Test Statistic = esc K 0 71 hours #3 72 W Q D 64 25 ום
The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a 1% level of significance. Give answer to at least 4 decimal places. Hours 50 46 55 52 45 66 58 60 46 46 52 53 What are the correct hypotheses? H0: hoursH1: hours Based on the hypotheses, find the following:Test Statistic=p-value= The correct decision is to . The correct summary would be: that the mean number of hours of all employees at start-up companies work more than the US mean of 47 hours.
The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a 5% level of significance. Give answer to at least 4 decimal places. Hours 46 42 54 54 48 62 58 47 49 48 53 52 a. What are the correct hypotheses? Ho: Select an answer b. Test Statistic = ♥ H₁: Select an answer ? Based on the hypotheses, find the following: c. p-value = ? hours hours O d. The correct decision is to Select an answer e. The correct summary would be: Select an answer that the mean number of hours of all employees at start-up companies work more than the US mean of 47 hours.
In its Fuel Economy Guide for 2016 model vehicles, the Environmental Protection Agency gives data on 1170 vehicles. There are a number of high outliers, mainly hybrid gas‑electric vehicles. If we ignore the vehicles identified as outliers, however, the combined city and highway gas mileage of the other 1146 vehicles is approximately Normal with mean 23.0 miles per gallon (mpg) and standard deviation 4.9 mpg. The 2016 Volkswagen Beetle with a four‑cylinder 1.8‑L engine and automatic transmission has combined gas mileage of 28 mpg. Find the percentage of 2016 vehicles that have better gas mileage than the Beetle's gas mileage. (Enter your answer rounded to two decimal places.)
Use the appropriate statistical table. In 2002, the average duration of incoming telephone calls to a furniture store was 9.4 minutes. The manager wants to perform a test to determine whether this average duration of incoming calls has changed. Twenty calls to the store was randomly selected and the mean duration was 10.2 minutes with standard deviation 4.8 minutes.Using a 1% level of significance, test whether the mean duration of incoming calls tothe store had changed.
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 22.4 with a standard deviation of 4.4, while the 200 students in group 2 had a mean score of 19.8 with a standard deviation of 4.1. Complete parts (a) and (b) below. (a) Determine the 90% confidence interval for the difference in scores, μ₁ −μ₂. Interpret the interval. The lower bound is The upper bound is (Round to three decimal places as needed.) Interpret the interval. Choose the correct answer below. OA. There is a 90% probability that the difference of the means is in the interval. B. The researchers are 90% confident that the difference of the means is in the interval. C. The…
Salvatore, as the director of a regional bank, is concerned about the wait times of customers at the four branches. He randomly selects 48 patrons at each branch and records the waiting time for each patron. The results of the samples are shown below. The Alvrine branch has a mean waiting time of 13.49 minutes with a standard deviation of 1.97 minutes.The Durham branch has a mean waiting time of 12.61 minutes with a standard deviation of 2.89 minutes.The Hanover branch has a mean waiting time of 11.06 minutes with a standard deviation of 2.46 minutes.The Mascomonet branch has a mean waiting time of 12.89 minutes with a standard deviation of 3.12 minutes.
A bridal gown shop owner owns a store in San Francisco and a store in Redwood city. She is trying to figure out if clients tend to spend the same amount at both stores. She takes a random sample of 25 purchases from each store, and find the San Francisco store has a mean amount spent of $2500 with a standard deviation of $1500. The Redwood City store has a mean amount spent of $2000 with a standard deviation of $1000. Use a significance level of 10% to determine if the clients at the two stores spend the same amounts. State: Plan: Do: Conclude:
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Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 24.4 with a standard deviation of 3.8, while the 200 students in group 2 had a mean score of 15.7 with a standard deviation of 3. Complete parts (a) and (b) below. (a) Determine the 95% confidence interval for the difference in scores, µ, - H3. Interpret the interval. The lower bound is The upper bound is (Round to three decimal places as needed.)
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 23.5 with a standard deviation of 4.3, while the 200 students in group 2 had a mean score of 17.7 with a standard deviation of 4.1. Complete parts (a) and (b) below. (a) Determine the 95% confidence interval for the difference in scores, μ1−μ2. Interpret the interval. The lower bound is __. The upper bound is ___ (Round to three decimal places as needed.) B Interpret the interval. Choose the correct answer below. A. The researchers are 95% confident that the difference of the means is in the interval. B. There is a 95% probability that the difference of the means is…